Radii and chord form an equilateral triangle. The angle of the larger segment is

.
The length of the larger segment is
2(4 + 2x) ≥ 5x + 5
Simplify.
8 + 4x ≥ 5x + 5
Subtract 8 from both sides, as well as subtracting 5 from both sides.
4x - 5x ≥ 5 - 8
Simplify.
-x ≥ -3
Divide both sides by -1.
x ≤ 3
~Hope I helped!~
check the picture below.
![\bf tan(22^o)=\cfrac{x}{80}\implies \boxed{80tan(22^o)=x} \\\\[-0.35em] ~\dotfill\\\\ tan(43.5^o)=\cfrac{y+x}{80}\implies 80tan(43.5^o)=y+x\implies 80tan(43.5^o)-x=y \\\\\\ 80tan(43.5^o)-80tan(22^o)=y\implies 43.59506727037783689501 \approx y \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{rounded~up}{44=y}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20tan%2822%5Eo%29%3D%5Ccfrac%7Bx%7D%7B80%7D%5Cimplies%20%5Cboxed%7B80tan%2822%5Eo%29%3Dx%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A~%5Cdotfill%5C%5C%5C%5C%0Atan%2843.5%5Eo%29%3D%5Ccfrac%7By%2Bx%7D%7B80%7D%5Cimplies%2080tan%2843.5%5Eo%29%3Dy%2Bx%5Cimplies%2080tan%2843.5%5Eo%29-x%3Dy%0A%5C%5C%5C%5C%5C%5C%0A80tan%2843.5%5Eo%29-80tan%2822%5Eo%29%3Dy%5Cimplies%2043.59506727037783689501%20%5Capprox%20y%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A~%5Chfill%20%5Cstackrel%7Brounded~up%7D%7B44%3Dy%7D~%5Chfill)
make sure your calculator is in Degree mode.
Answer:
See Below.
Step-by-step explanation:
We want to verify:

We will utilize the following identities:

And:

So, by substitution, we acquire:

Distribute:

The first and third term will cancel:

Combine like terms:

Answer:
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Step-by-step explanation: