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adell [148]
3 years ago
15

A tortoise and a hare are competing in a 2000-meter race. The arrogant hare decides to let the tortoise have a 510-meter head st

art. When the start gun is fired the hare begins running at a constant speed of 8 meters per second and the tortoise begins crawling at a constant speed of 5 meters per second. Define a function f to represent the tortoise's distance from the finish line (in meters) in terms of the number of seconds t since the start of the race.
Mathematics
1 answer:
Nataliya [291]3 years ago
8 0

The distance covered by the hare and the tortoise in t seconds are 8t and 5t respectively. (Simple Speed-Distance-Time relation)

The tortoise gets a 510m headstart so at t=0 is 1490m.

The functions representing the distance of both of them from the finish line is,

F(x)=2000-8t,. for hare

G(x)=1490-5t,. for tortoise

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3 years ago
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Brums [2.3K]

Answer:

Option B

Step-by-step explanation:

(q + p)q = (s + r)s

Lets open the brackets of L.H.S.

=> q^2 + pq = (s+ r)s

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=> q^2 + pq - q^2 = (s + r)s - q^2

=> pq = (s + r)s - q^2

Lets divide both the sides by q.

=> \frac{pq}{q} = \frac{(s + r)s - q^2}{q}

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5.) 2x=-8
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x+4y=4
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3 years ago
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