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ira [324]
3 years ago
13

Write the vertex and indicate if the graph opens up or down.

Mathematics
2 answers:
Reil [10]3 years ago
7 0
The answer is A,) (-2,-5) because I just did it in my CASIO calculator
Tatiana [17]3 years ago
5 0
Complee the square to get into for
y=a(x-h)^2+k
(h,k) is vertex
if a is positive, it opens up
if a is negative, it opens down

so
y=2x²+8x+3
y=(2x²+8x)+3
y=2(x²+4x)+3
take 1/2 of 4 and square it
4/2=2, 2²=4
ad negative and positive of it inside
y=2(x²+4x+4-4)+3
factor pefect square
y=2((x+2)²-4)+3
distribute
y=2(x+2)²-8+3
y=2(x+2)²-5
y=2(x-(-2))²+(-5)
vertex isi (-2,-5)
2 is positive so it opens up


(-2,-5) up
A is answer
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6 0
3 years ago
2x + y = 12<br> 4x - 3y = 2
7nadin3 [17]

Answer:

The value of x for equation is 3.4

The value of y for equation is 5.2  

Step-by-step explanation:

Given as :

The two linear equation are

2 x + y = 12           ........A

4 x - 3 y = 2              .........B

Now, Solving both equations , we get

3 × ( 2 x + y ) + (4 x - 3 y) = 3 × 12 - 2

Or, 6 x + 3 y + 4 x - 3 y = 36 - 2

Or, (6 x + 4 x) + (3 y - 3 y) = 34

Or, 10 x + 0 = 34

∴  x = \dfrac{34}{10}

i.e x = 3.4

So, The value of x for equation , x = 3.4

Put the value of x into eq A

∵ 2 x + y = 12

Or, y = 12 - 2 x

Or, y = 12 - 2 × 3.4

Or, y = 12 - 6.8

∴ y = 5.2

So, The value of y for equation , y = 5.2

Hence, The value of x for equation is 3.4  and The value of y for equation is  5.2   Answer

4 0
3 years ago
Which image shows the correct position of -2 1/2on the number line?
ohaa [14]
The answer to your question would be 'A'
5 0
3 years ago
Determine whether each relation is a function. Give the domain and range for each relation.
brilliants [131]

Answer:

Not a function

Domain: {3,4}

Range: {4,5}

Step-by-step explanation:

A function is a relation where each input has its own output. In other words if the x value has multiple corresponding y values then the relation is not a function

For the relation given {(3, 4), (3, 5), (4, 4), (4, 5)} the x value 3 and 4 have more than one corresponding y value therefore the relation shown is not a function

Now let's find the domain and range.

Domain is the set of x values in a relation.

The x values of the given relation are 3 and 4 so the domain is {3,4}

The range is the set of y values in a relation

The y value of the given relation include 4 and 5

So the range would be {4,5}

Notes:

The values of x and y should be written from least to greatest when writing them out as domain and range.

They should be written inside of brackets

Do not repeat numbers when writing the domain and range

3 0
3 years ago
I’m kind of lazy to answer this question can somebody answer this for me
kirill [66]

Answer:

everyone got 6 pieces

Step-by-step explanation:

do you actually need a explanation?

4 0
3 years ago
Read 2 more answers
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