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Nataliya [291]
3 years ago
12

Find the measure of the indicated aces and angles

Mathematics
1 answer:
Serggg [28]3 years ago
4 0

Answer:

a=21

b=69

c=42

d=138

Step-by-step explanation:

c is supplementary to d (which is 138), so c=180-138= 42.

angle b is on the edge of the central angle 138, so b is 1/2, therefore, b=69.

angle a is complementary to angle b because any triangle that includes the diameter is a right angle, so angle a=90-69=21.

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Will mark brainliest! Questions are in the picture!
alexdok [17]

Answer:

52.9 inches .

Step-by-step explanation:

Given that the triangular indentation has an area of 100 in.² and the base and height of this traingle are represented by expressions 3x and x+3 respectively . We need to find out the <u>perimeter </u>to the nearest tenth.

As we know that the area of triangle is ,

\rm\longrightarrow Area_{\triangle}=\dfrac{1}{2}(base)(height)

Substituting the respective values,

\rm\longrightarrow 100\ =\dfrac{1}{2}(x+3)(3x)\\\\\rm\longrightarrow 2(100) = 3x(x+3)\\\\\rm\longrightarrow200 = 3x^2+9x\\\\\rm\longrightarrow 3x^2+9x-200=0

On using the <u>Quadratic</u><u> formula</u> , we have;

\rm\longrightarrow x =\dfrac{-9\pm\sqrt{9^2-4(3)(-200)}}{2(3)} \\\\\rm\longrightarrow x =\dfrac{-9\pm \sqrt{81+1200}}{6}\\\\\rm\longrightarrow x =\dfrac{-9\pm \sqrt{1281}}{6}

On simplifying above , we will get ,

\rm\longrightarrow x = 6.802,-9.802

Since sides can't be negative, therefore,

\rm\longrightarrow\underline{\underline{ x =6.802}}

Therefore ,

  • \rm\longrightarrow Base = 3x =3(6.802)in = 20.406\ in\\
  • \rm\longrightarrow Height = x +3=6.802+3=9.802\ in

Next let's find out the <u>hypotenuse </u>using Pythagoras theorem, as ;

\rm\longrightarrow h=\sqrt{ b^2+p^2}\\

\rm\longrightarrow h =\sqrt{ (20.406)^2+(9.802)^2}\\

\rm\longrightarrow h =\sqrt{416.40+96.07}\\

\rm\longrightarrow h = 22.63\ in

Now we may find perimeter as ,

\rm\longrightarrow P = p + b + h \\

\rm\longrightarrow P = (22.63 + 9.802 + 20.406)in.

\\\rm\longrightarrow P = 52.89 \ in.\\

\rm\longrightarrow \underline{\underline{ Perimeter = 52.9\ in .}}

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