Answer:
40 degrees
Step-by-step explanation:
Angle ACO = 80 ( 180 - 100)
Angle CAO = 60 (180 - 120)
Angle AOC = 40 (180 - 80 - 60) (TOTAL DEGREES OF A TRIANGLE IS 180)
Since the exponent is negative, you move the decimal (2.0) to the left two spots leaving you with .02
Cosine is adjacent/hypotenuse
The adjacent side to angle F is 60, and the hypotenuse is 61
Therfore, C) 60/61 would be the correct choice
hope this helps:)
Using the following equation is how you translate degrees Fahrenheit to Kelvin:
Kelvin = (Fahrenheit + 459.67) * 5 / 9<span>
or you could use:
</span>
Kelvin = (Fahrenheit - 32) * 5 / 9 + 273.15<span> </span>
Differentiate both sides of the equation of the circle with respect to
, treating
as a function of
:

This gives the slope of any line tangent to the circle at the point
.
Rewriting the given line in slope-intercept form tells us its slope is

In order for this line to be tangent to the circle, it must intersect the circle at the point
such that

In the equation of the circle, we have

If
, then
, so we omit this case.
If
, then
, as expected. Therefore
is a tangent line to the circle
at the point (1, -2).