<span>Gary spend 13 hours per week on the Internet and 13 hours on video games Gary has 5 hours of free time each day,
so total free time in a week=> 7*5=35 hours
Now he spends 13+13 hours on the internet and games=28 hours Percentage free time spent on games and internet
26/35 (that is a fraction) x100 =</span><span>74.285714
</span>so round your answer
<span>Triangle Inequality Theorem
</span><span>the sum of two side lengths of a triangle is always greater than the third side.
</span>
5+8=13
your answer = no
A student who studies 10 hours per week should earn a score of 95
I believe it should be B because it says one more than twice the number so that means addition. Also it says twice the number so that should be 2w.
I’m not 100% sure but it is my best guess
Answer:
- hits the ground at x = -0.732, and x = 2.732
- only the positive solution is reasonable
Step-by-step explanation:
The acorn will hit the ground where the value of x is such that y=0. We can find these values of x by solving the quadratic using any of several means.
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<h3>graphing</h3>
The attachment shows a graphing calculator solution to the equation
-3x^2 + 6x + 6 = 0
The values of x are -0.732 and 2.732. The negative value is the point where the acorn would have originated from if its parabolic path were extrapolated backward in time. Only the positive horizontal distance is a reasonable solution.
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<h3>completing the square</h3>
We can also solve the equation algebraically. One of the simplest methods is "completing the square."
-3x^2 +6x +6 = 0
x^2 -2x = 2 . . . . . . . . divide by -3 and add 2
x^2 -2x +1 = 2 +1 . . . . add 1 to complete the square
(x -1)^2 = 3 . . . . . . . . written as a square
x -1 = ±√3 . . . . . . . take the square root
x = 1 ±√3 . . . . . . . add 1; where the acorn hits the ground
The numerical values of these solutions are approximately ...
x ≈ {-0.732, 2.732}
The solutions to the equation say the acorn hits the ground at a distance of -0.732 behind Jacob, and at a distance of 2.732 in front of Jacob. The "behind" distance represents and extrapolation of the acorn's path backward in time before Jacob threw it. Only the positive solution is reasonable.