Answer:
Check the explanation
Step-by-step explanation:
(a)Let p be the smallest prime divisor of (n!)^2+1 if p<=n then p|n! Hence p can not divide (n!)^2+1. Hence p>n
(b) (n!)^2=-1 mod p now by format theorem (n!)^(p-1)= 1 mod p ( as p doesn't divide (n!)^2)
Hence (-1)^(p-1)/2= 1 mod p hence [ as p-1/2 is an integer] and hence( p-1)/2 is even number hence p is of the form 4k+1
(C) now let p be the largest prime of the form 4k+1 consider x= (p!)^2+1 . Let q be the smallest prime dividing x . By the previous exercises q> p and q is also of the form 4k+1 hence contradiction. Hence P_1 is infinite
He should add exact since money is involved
he could also estimate since they are so close together, but he would be off only 2 cents
A
Answer:
2
Step-by-step explanation:
13x2=26
14x3=42
Greatest common Factor of 26 and 42 is 2
Answer:
X 1 = -4,X 2 =12
EXPLANATION:
Determine the defined range
X+6/x=6/x-8,x#0,x#8
Simplify the equation using cross-multiplication
(X+6) x (x-8)=6x
Move variable to the left-hand side and change its sign
(X-6)x(x-8)-6x=0
Multiply the parentheses
X^2-8x+6x-48-6x=0
Since two opposites add up to zero, remove them from the expression
X^2-8x-48=0
Write -8x as a difference
X^2+4x-12x-48=0
Factor out x from the expression
Xx(x+4)-12x-48=0
Factor out -12 from the expression
Xx(x+4)-12(x+4)=0
Factor out from the expression
(x+4)x(x-12)=0
When the product of factors equals 0, at least one factor is 0
x+4=0
x-12=0
Solve the equation for x
X=-4
X-12=0
X=-4,x#0,x#8
Check if the solution is in the defined range
X=-4
x=12
The equation has 2 solutions
X 1 = -4,X 2 =12
Hope this helps
