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Alekssandra [29.7K]

2 years ago

9

Jose needs to enclose a rectangular section of his yard. The perimeter of the section is 27 feet, and the area is 35 square foot

. Find the length and width of the section.
The equation for the perimeter is p=2(L+W). If the perimeter is 27 feet, solve for W. show your work

1 answer:

Ratling [72]2 years ago

3 0

A = 35 sq ft
<span>L = 10 ft </span>
<span>W = 3.5 ft</span>

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Write the fraction or mixed number as a decimal. 1. 8 4/100 2. 4/10 3. 4 7/100 4. 6/10 5. 8 3/100 6. 8/10 7. 4/100 8. 10 14/100

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8 4/100 = 8.04, as the ".00" is out of 1.00.
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3 years ago

Find the surface area of a square pyramid with side length 4 mi and slant height 5 mi.

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2 years ago

Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.

mart [117]

Answer:

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

Step-by-step explanation:

The given expression is

$\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}$

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Using properties of exponents, we get

$\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}$ $[\because a^ma^n=a^{m+n}]$

$\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}$

$\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is $\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

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