3 years ago

Select all the expressions that are equivalent to -6(3x - 7).

Mathematics

1 answer:

Likurg_2 [28]3 years ago

8 0

Answer:-18x+42

Step-by-step explanation:

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Plz help i dont know how to do this

liubo4ka [24]

Answer:

Step-by-step explanation:

g to the power of 8 *h hope this helped

nh to the power of 8

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3 years ago

Sara used 6_1/2 packs of pencils in the first 1/2 of the year. At what rate is Sara using pencils?

Verizon [17]

13 packs a year. 6.50 (.50 comes from 1/2) since the question states that she uses 6_1/2 packs of pencils in the first “1/2” of the year we need to multiply the 6_1/2 by 2 and we get our answer.

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2 years ago

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Simify the following expression (show work ) IF YOU CAN

Mashutka [201]

$(4d)(6d)(0.25d)=d^3[(4)(6)(0.25)]=\boxed{6d^3}$

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2 years ago

What is the slope of the line shown?

Viefleur [7K]

Answer:

the answer is b, 1/2.

Step-by-step explanation:

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3 years ago

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Assume that women's heights are normally distributed with a mean given by mu equals 62.5 in, and a standard deviation given by

kirza4 [7]

Answer: a) The probability is approximately = 0.5793

b) The probability is approximately=0.8810

Step-by-step explanation:

Given : Mean : $\mu= 62.5\text{ in}$

Standard deviation : $\sigma = \text{2.5 in}$

a) The formula for z -score :

$z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

Sample size = 1

For x= 63 in. ,

$z=\dfrac{63-62.5}{\dfrac{2.5}{\sqrt{1}}}=0.2$

The p-value = $P(z$

$0.5792597\approx0.5793$

Thus, the probability is approximately = 0.5793

b) Sample size = 35

For x= 63 ,

$z=\dfrac{63-62.5}{\dfrac{2.5}{\sqrt{35}}}\approx1.18$

The p-value = $P(z$

$= 0.8809999\approx0.8810$

Thus , the probability is approximately=0.8810.

6 0

4 years ago