The <em>quadratic</em> equation has the following results: (p, q) = (8, 15), minimum point: (h, k) = (1, 4), range of values: - 4 < x < - 3
<h3>How to analyze quadratic equations</h3>
In this question we have a <em>quadratic</em> equation of the form y = x² + p · x + q , whose <em>missing</em> coefficients can be found by solving on the following system of <em>linear</em> equations:
- 5 · p + q = - 25
- 3 · p + q = - 9
(p, q) = (8, 15)
The vertex represents the <em>minimum</em> point, which is found by changing the form of the equation from <em>standard</em> form into <em>vertex</em> form:
y = x² + 8 · x + 15
y + 1 = x² + 8 · x + 16
y + 1 = (x + 4)²
(h, k) = (1, 4)
And lastly we must solve for x in the following inequality:
x² + 8 · x + 15 < x + 3
x² + 7 · x + 12 < 0
(x + 3) · (x + 4) < 0
- 4 < x < - 3
To learn more on quadratic equations: brainly.com/question/2263981
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Answer:
a)
b)
c)
d)
Step-by-step explanation:
We solve this using backward or forward substitution.
a) We have this:
then:
for we have:
from this, we can see that is a solution for this recurrence relation, where . This is:
b) We have with . Then:
but at the same time
we have:
or
by the next:
We can see that the recurrence rule is:
this is
c)Note that:
taking all this we have to:
then:
this is:
d)We take . Then:
replacing we have:
I think 1/3 i dont know for sure tho
Answer: (A1+A2) × B1
Step-by-step explanation:
Here, at first we have two values that are and
And, when we add these values we get =
Now when we multiply by
We get,
Thus, third Option is correct.