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3 years ago

Which equation represents the line shown on the graph?

Mathematics

2 answers:

Firlakuza [10]3 years ago

5 0

Hello there,

To find out the equation you need to use slope intercept form...

y = mx + b

The only equation above that follows that form is...

y = 2x

Hope I helped!!

-Char

tino4ka555 [31]3 years ago

4 0

Answer:

y = 2x

Step-by-step explanation:

We first find the y-intercept. This is the point where the line crosses the y-axis.

We can see in this graph that the line crosses the y-axis at (0, 0). This makes the y-intercept 0.

Next we find the slope. In a graph, we can do this by finding the rise/run; the rise is the vertical change between two points and the run is the horizontal change between two points.

The rise between points is 2 and the run is 1; this makes the slope 2/1 = 2.

Slope-intercept form is y=mx+b, where m is the slope and b is the y-intercept. This makes the equation of our line y = 2x+0 or y = 2x.

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3 years ago

graph the line that passes through the point (0, -3) and is perpendicular to another line whose slope is 2

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Answer:

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Step-by-step explanation:

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3 years ago

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Taking derivative of both sides, we get:
$\frac{d}{da}(s(a))= \frac{d}{da}( 0.882 a^{0.842})$

Taking the common out from right hand side of the equation:
$s'(a)= 0.882\frac{d}{da}(a^{0.842})$

Applying the power rule of derivative:

$s'(a) = 0.882 ( 0.842 a^{(0.842-1)}) \\ s'(a) = 0.742644 a^{-0.158}$

Now we can substitute 107 in place of a to get s'(107):
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Thus the value of s'(107) rounded to 5 decimal places is 0.35494

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