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s2008m [1.1K]
3 years ago
15

3. IF ON = 5x - 7, LM = 4x +4, NM = x - 7, and OL = 3y – 4, find the values of x and y for which LMNO must

Mathematics
1 answer:
kkurt [141]3 years ago
3 0

Answer:

x = 11 and y = \frac{8}{3}

Step-by-step explanation:

If LMNO is a parallelogram then it's opposite sides will be equal.

So, LM = ON

⇒ 4x + 4 = 5x - 7

⇒ x = 11

Now, MN = OL  

⇒ x - 7 = 3y - 4

⇒ 11 - 7 = 3y - 4 {Since we already have, x = 11}

⇒ y = \frac{8}{3} (Answer)

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LekaFEV [45]
<h3><u>Explanation</u></h3>
  • Convert the equation into slope-intercept form.

y = mx + b

where m = slope and b = y-intercept.

What we have to do is to make the y-term as the subject of equation.

9x - 3y = 15 \\ 9x - 15 = 3y \\  \frac{9x - 15}{3}  = y

  • Simplify

\frac{9x}{3}  -  \frac{15}{3}  = y \\ 3x - 5 = y  \\ y = 3x - 5

From y = mx+b, the slope is 3.

<h3><u>Answer</u></h3>

\large \boxed {slope = 3}

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3 years ago
What is the 7.05 % of 1,051,50
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Which is f(6) for the quadratic function graphed?<br> 0 -2<br> * -0.5<br> 1.5<br> 4
rusak2 [61]

Answer:

4

Step-by-step explanation:

I'm pretty sure theres a graph to this so....

The given parabolic graph of quadratic function

To find:What is F(6) for the quadratic function

Solution:We have given graph of quadratic function

there is a different value for Y and a different value for X

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here X=6, need to find graph of quadratic function

X=6

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4 0
3 years ago
Allowing 20% discount on the marked price. of 아 a watch, the value of the watch will be Rs. 2378. If the VAT of 10% is added, fi
Harrizon [31]

Answer:

The marked price of the watch is $2,702.27.

Step-by-step explanation:

Since allowing 20% discount on the marked price of a watch, the value of the watch will be Rs. 2378, to determine, if the VAT of 10% is added, it's marked price, the following calculation must be performed:

1 - 0.2 = 0.8

0.8 x 1.1 = 2378

0.88 = 2378

0.88 = 2378

0.8 = X

0.8 x 2378 / 0.88 = X

1,902.4 / 0.88 = X

2,161.81 = X

0.8 = 2,161.81

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4 0
3 years ago
Find the number b such that the line y = b divides the region bounded by the curves y = 36x2 and y = 25 into two regions with eq
Gemiola [76]

Answer:

b = 15.75

Step-by-step explanation:

Lets find the interception points of the curves

36 x² = 25

x² = 25/36 = 0.69444

|x| = √(25/36) = 5/6

thus the interception points are 5/6 and -5/6. By evaluating in 0, we can conclude that the curve y=25 is above the other curve and b should be between 0 and 25 (note that 0 is the smallest value of 36 x²).

The area of the bounded region is given by the integral

\int\limits^{5/6}_{-5/6} {(25-36 \, x^2)} \, dx = (25x - 12 \, x^3)\, |_{x=-5/6}^{x=5/6} = 25*5/6 - 12*(5/6)^3 - (25*(-5/6) - 12*(-5/6)^3) = 250/9

The whole region has an area of 250/9. We need b such as the area of the region below the curve y =b and above y=36x^2 is 125/9. The region would be bounded by the points z and -z, for certain z (this is for the symmetry). Also for the symmetry, this region can be splitted into 2 regions with equal area: between -z and 0, and between 0 and z. The area between 0 and z should be 125/18. Note that 36 z² = b, then z = √b/6.

125/18 = \int\limits^{\sqrt{b}/6}_0 {(b - 36 \, x^2)} \, dx = (bx - 12 \, x^3)\, |_{x = 0}^{x=\sqrt{b}/6} = b^{1.5}/6 - b^{1.5}/18 = b^{1.5}/9

125/18 = b^{1.5}/9

b = (62.5²)^{1/3} = 15.75

8 0
4 years ago
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