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3 years ago

5

Please help!!! What is the equation of the line in slope-intercept form? Write your answer using integers, proper fractions, and

improper fractions in simplest form.

2 answers:

BabaBlast [244]3 years ago

6 0

Answer:

y = x - 40

Step-by-step explanation:

Points on the graph: (0, -40) and (60,20)

Slope:

m=(y2-y1)/(x2-x1)

m=(20+40)/(60-0)

m=60/60

m = 1

Slope-Intercept

y - y1 = m(x - x1)

y + 40 = 1(x -0)

y + 40 = x

y = x - 40

attashe74 [19]3 years ago

4 0

Answer:

y=-x-40

Step-by-step explanation:

Slope intercept form is y=mx+b

slope=rise/run

slope= -40/40 = -1

y-y1=m(x-x1)

y-(-40)= -1(x-0)

y+40=-x+0

y=-x+0-40

y=-x-40

hope that helps?

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Solve -1 3/8 K equals 2/3

guajiro [1.7K]

Answer:

K = -16/33

Step-by-step explanation:

For a problem like this, it is convenient to write the mixed number as an improper fraction:

-11/8 K = 2/3

Now, multiply the equation by the reciprocal of the coefficient of K.

K = (-8/11)(2/3)

K = -16/33

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3 years ago

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The answer is quadrant 2

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3 years ago

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1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

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2 years ago

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Write an equation to match each graph:please help me?<br><br>

Oksi-84 [34.3K]

Y = 5x
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3 years ago

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What is the measure of one angle of a regular convex 20-gon

Contact [7]

Answer:

The measure of one angle of a regular convex 20-gon is 162°

Step-by-step explanation:

* Lets explain how to solve the problem

- A convex polygon is a polygon with all the measures of its interior

angles less than 180°

- In any polygon the number of its angles equal the number of its sides

- A regular polygon is a polygon that is all angles are equal in measure

and all sides are equal in length

- The rule of the measure of an angle of a regular polygon is

$m=\frac{(n-2)180}{n}$ , where m is the measure of each interior

angle in the polygon and n is the numbers of the sides or the angles

of the polygon

* Lets solve the problem

- The polygon is convex polygon of 20 sides (20 angles)

- The polygon is regular polygon

∵ The number of the sides of the polygon is 20 sides

∴ n = 20

∵ The polygon is regular

∴ All angles are equal in measures

∵ The measure of each angle is $m=\frac{(n-2)180}{n}$

∴ $m=\frac{(20-2)180}{20}$

∴ $m=\frac{(18)180}{20}$

∴ $m=\frac{3240}{20}$

∴ m = 162

∴ The measure of one angle of a regular convex 20-gon is 162°

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3 years ago