minimum value of the quadratic function f(x) = x² - 2x + 7 is at x=1 & is (1, 6).
<u>Step-by-step explanation:</u>
Here we have , f(x) = x² - 2x + 7 or
. We need to find the minimum value of f(x) for which we need to differentiate it one time and equate it to zero . Value of x at which first differentiation of f(x) is zero will be the minimum value of function . Let's solve this:

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Now, value of function at x=1 is :

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Therefore, minimum value of the quadratic function f(x) = x² - 2x + 7 is at x=1 & is (1, 6).