Answer:
The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.
Step-by-step explanation:
<u>Equivalent algebraic expressions</u> are those expressions which on simplification give the same resulting expression.
Two algebraic expressions are said to be <u>equivalent</u> if their values obtained by substituting any values of the variables are same.
Two expressions 3f+2.6 and 2f+2.6 are not equivalent, because when f=1,

Method of substitution can only help her to decide the expresssions are not equivalent, but if she wants to prove the expressions are equivalent, she must prove it for all values of f.

This is true only when f=0.
Hence,
The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.
Answer:
y > 0 best describes the range of the function f(x) = 2(3)x. A function whose value is a constant raised to the power of the argument, especially the function where the constant is e
Step-by-step explanation:
Answer:
5.3-1.45=3.85
Step-by-step explanation:
she has 3.85 miles left to go because she already ran 1.45 and if you subtract that from the 5.3 you get 3.85 left to run.
F(x) = 3x - 5
f(2) = 3 (2) - 5
f (2) = 6-5
f (2) = 1
Answer:
Average rate of change = 0
Step-by-step explanation:
f(z) = -2z^2 - 12z - 19
a = -4 and b = -2
[f(b) - f(a)] / (b-a)
[-2(-2)^2 - 12(-2) -19] - [-2(-4)^2-12(-4)-19] / (-2 -(-4))
(-8+24-19) - (-32+48-19) / 2
(-8+24-19+32-48+19) / 2 = 0/2