Class 10R sat a test

Mathematics

1 answer:

Cerrena [4.2K]4 years ago

4 0

99% would of been boys so 1% of girls i think not sure

You might be interested in

A circle whose equation is (x-5)^2 + (y+1)^2=36 has a center,C and a radius, r, of

mamaluj [8]

Answer: The center is (5,-1) and radius is 6.

Step-by-step explanation: The equation: (x-h)^2+(y-k)^2=r^2 is really important. Since we have 36 equal r^2, square root it to get 6. And the center would be 5, because (x-5) but do the opposite operation, same for y+1.

3 0

3 years ago

Heidi is designing a two-lane running track for an athletic club the track will go around a regtangle that will have an area of

solong [7]

Answer:

i was asking the same question srry ion know adyyy daddy

Step-by-step explanation:

7 0

3 years ago

What is a simple way to solve for the sum and difference of 2 cubes? For example, 27+64<img src="https://tex.z-dn.net/?f=x%5E3"

salantis [7]

Answer:

(3 + 4x)(9 - 12x + 16x²) = 0

(4m - 1)(16m² + 4m + 1) = 0

Step-by-step explanation:

Here we have to solve the sum of two cubes which is $27 + 64x^{3}$

Now, the equation is $27 + 64x^{3} = 0$

⇒ 3³ + (4x)³ = 0

⇒ (3 + 4x)[3² - 3(4x) + (4x)²] = 0

⇒ (3 + 4x)(9 - 12x + 16x²) = 0

So, (3 + 4x) = 0 or (9 - 12x + 16x²) = 0

Therefore, from the above two relation we can solve for x.

One root will be $- \frac{3}{4}$ and the others we will get by applying Sridhar Acharya Formula, which will give a pair of conjugate imaginary roots of the equation.

Again, we have to solve the difference of two cubes which is $64m^{3} - 1$

Now, the equation is $64m^{3} - 1 = 0$

⇒ (4m)³ - 1³ = 0

⇒ (4m - 1)[(4m)² + 4m(1) + 1²] = 0

⇒ (4m - 1)(16m² + 4m + 1) = 0

So, (4m - 1) = 0 or (16m² + 4m + 1) = 0

Therefore, from the above two relation we can solve for m.

One root will be $\frac{1}{4}$ and the others we will get by applying Sridhar Acharya Formula, which will give a pair of conjugate imaginary roots of the equation. (Answer)