Answer:
Variance of difference between pre-exam and post-exam grades = 10.8
Step-by-step explanation:
Correlation (X,Y) = Covariance (X,Y) / √ { Variance (X) . Variance (Y) }
Given : Correlation (Pre & post exam grade) = 0.9 ; Variance (Pre exam grade) = 0.90 ; Variance (Post exam grade) = 16
So, 0.9 = Covariance (X,Y) / √ { 16 x 9 }
0.9 = Covariance (X,Y) / 12
Covariance (X,Y) = 12 x 0.9 = 10.8
Answer:
6^-12
Step-by-step explanation:
Formula : -
a^m / a^n = a^( m - n )
Here,
a = 8
m = 4
n = 16
8^4 / 8^16
= 6^( 4 - 16 )
= 6^-12
Answer is $244.50 since he anything over 40 hours is time and a half
Answer:
Step-by-step explanation:
72/2 = 36
bisected means.divide into two parts
answer in 36
I got 9.8
6x^2+13x-5=0
36x+13x-5=0
+5 +5
36x+13x=5
49x=5
5 5
X=9.8