I think it’s (3,4) the third answer
Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Answer:
Step-by-step explanation:
First, you make fourteen a fraction.
Then, make it a mixed fraction by adding a six.
Lastly, have a great day! :)
Step-by-step explanation:
the asymptotes of f(x) :
(4x-π) = π/2
4x = 3π/2 => x = 3π/8
(4x-π) = 3π/2
4x=5π/2 => x = 5π/8
the answer is
D. X= 3pi/8, x=5pi/8
