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3 years ago

Triangle ABC is reflected over the Y axis. what are the coordinates of the reflected triangle

Mathematics

2 answers:

Liula [17]3 years ago

8 0

Original Coordinates: A(1, 3) B(4, 5) C(3, 1)

Now, It is reflected over y-axis, so the sign of their x-coordinate will change.,

It would be: A'(-1, 3) B'(-4, 5) C'(-3, 1)

Hope this helps!

V125BC [204]3 years ago

8 0

Answer:

A'(-1,3),B'(-4,5),C'(-3,1).

Step-by-step explanation:

The coordinates of the vertex of the given triangle are A(1,3) ,B(4,5) ,C(3,1).

When a point is reflected along the y axis the y value f the point (x,y) remains the same while x changes its sign.

Point (x,y) will have the reflected pint x'(-x,y)

The reflected points along the y axis are:

A(1,3) ......A'.(-1,3)

B(4,5).......B'(-4,5)

C(3,1)........C'(-3,1)

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Find the measure of angle x

Triss [41]

Answer:

it is heptagon and sum of interior angles of heptagon is 900 °

123°+131°+ 125°+124°+x 129°+132° = 900°

764° +x = 900 °

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3 years ago

A doctor released the results of clinical trials for a vaccine to prevent a particular disease. In these clinical trials, 200,0

CaHeK987 [17]

Answer:

1) No, there is not enough evidence to support the claim that the vaccine was effective (P-value=0.104) .

The null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0$

being the subindex 1 for the experimental group and subindex 2 for the control group.

2) Test statistic z=-1.26

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the vaccine was effective.

Then, the null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0$

The significance level is 0.01.

The sample 1 (experimental group), of size n1=100000 has a proportion of p1=0.0002.

$p_1=X_1/n_1=21/100000=0.0002$

The sample 2 (control group), of size n2=100000 has a proportion of p2=0.0003.

$p_2=X_2/n_2=30/100000=0.0003$

The difference between proportions is (p1-p2)=-0.0001.

$p_d=p_1-p_2=0.0002-0.0003=-0.0001$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{21+30}{100000+100000}=\dfrac{51}{200000}=0.00026$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.00026*0.99974}{100000}+\dfrac{0.00026*0.99974}{100000}}\\\\\\s_{p1-p2}=\sqrt{0+0.0000000025}=\sqrt{0.0000000051}=0.000071$