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liberstina [14]
3 years ago
14

Construct a 95​% confidence interval estimate of the mean net change in ldl cholesterol after the garlic treatment. what does th

e confidence interval suggest about the effectiveness of garlic in reducing ldl​ cholesterol?
Mathematics
1 answer:
nikitadnepr [17]3 years ago
5 0

 Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL​cholesterol?

sample mean = x-bar = 4.7
ME = 1.96*15.6/sqrt(43) = 4.663

95% CI: 4.7 - 4.663 < u < 4.7 + 4.663

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Answer:

3

Step-by-step explanation:

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3 years ago
Hypothesis testing on samples with fewer than 30 participants can be carried out by using the t-value for the corresponding leve
Eva8 [605]

Answer: true

Step-by-step explanation:

Z-tests are statistical calculations that can be used to compare the population mean to a sample mean The z-score is used to tellsbhow far in standard deviations a data point is from the mean of the data set. z-test compares a sample to a defined population and is typically used for dealing with problems relating to large samples (n > 30). Z-tests can also be used to test a hypothesis. Z-test is most useful when the standard deviation is known.

Like z-tests, t-tests are used to test a hypothesis, but a t-test asks whether a difference between the means of two groups is not likely to have occurred because of random chance. Usually, t-tests are used when dealing with problems with a small sample size (n < 30).

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3 0
3 years ago
Round to the nearest thousandth 0.416
Liula [17]
Here is the value of each decimal digit value

.4⇒ tenths place

.01⇒hundredths place

.006,thousandths place

So .416 is .416 rounded since there is nothing to round to

In other words, its already rounded to the nearest thousandths 
Its kinda a trick question to make sure you know your place values
3 0
3 years ago
At the beginning of the day there were 90 little fish in the pond.At the end of the day there were 52 little fish in the pond.Fi
balu736 [363]

Answer:

42%

Step-by-step explanation:

The first step is to calculate the difference in the number of fishes from the beginning of the day to the end of the day.

90 -52

= 38 fishes

Therefore the percent decrease can be calculated as follows

= 38/90 × 100

= 0.422 × 100

= 42.2 %

= 42% ( to the nearest cent)

8 0
3 years ago
Maria is comparing the prices of two window cleaning companies. Company A charges $6 per window and an additional $12 as service
rewona [7]
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8 0
3 years ago
Read 2 more answers
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