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larisa86 [58]
3 years ago
5

HELP NEED HELP FAST ANSWER FAST PLEZ

Mathematics
1 answer:
vodomira [7]3 years ago
4 0

Answer

nvm................

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What is the length of segment DB?
tatyana61 [14]
I believe it’s 82

8x=3x+8+4x+10
x=18

4•18+10=72+10=82
3 0
3 years ago
The change of rate is
irakobra [83]

ROC is often used when speaking about momentum, and it can generally be expressed as a ratio between a change in one variable relative to a corresponding change in another; graphically, the rate of change is represented by the slope of a line. The ROC is often illustrated by the Greek letter delta.

Hope this helps!

5 0
3 years ago
Which of the following is equivalent to log 7^ 50 rounded to three decimal places?
otez555 [7]
7^50
= 1.798 × 10^42

i am a mathematics teacher. if anything to ask please pm me
4 0
3 years ago
The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas
saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by s(t) = -t^3+3t^2+7t +4, where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

s(t) = -t^3+3t^2+7t +4

Derivate w.r.t. time,

v(t)=s'(t) = -3t^2+6t+7

It is a quadratic function so its maximum is at vertex of the function.

The x point of the function is given by,

x=-\frac{b}{2a}

Where, a=-3, b=6 and c=7

t=-\frac{6}{2(-3)}

t=-\frac{6}{-6}

t=1

As 1 lie between interval [0,4]

Substitute t=1 in the function,

v(t)= -3(1)^2+6(1)+7

v(t)= -3+6+7

v(1)=10

Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0
3 years ago
Read 2 more answers
You are playing tennis with a friend.The path of the tennis ball after you return to a serve can be modeled by the function y=-0
Ivahew [28]
#1) 4.445 ft
#2) yes

Explanation
#1) The maximum height is the y-coordinate of the vertex.  We first find the axis of symmetry, given by x=-b/2a:

x=-0.17/2(-0.005) = -0.17/-0.01 = 17

Plugging this into the equation,
y=-0.005(17²)+0.17(17)+3 = 4.445

#2) Substituting 30 into the equation,
y=-0.005(30²) + 0.17(30) + 3 = 3.6

The ball will 3.6 in the air, so yes, it will clear the 3 ft tall net.
4 0
3 years ago
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