All categories

2 years ago

What is the difference between the 5th multiple of 7 and 3rd multiple of 2 ?

Mathematics

1 answer:

lesya692 [45]2 years ago

4 0

Answer:

<h3>5th Multiple of 7 = 35</h3><h3>3rd Multiple of 2 = 6</h3><h2>The Difference</h2>

=> 35-6

You might be interested in

Sam does 11 jumping jacks in 8 seconds. If he does the jumping jacks at a constant rate, how many jumping jacks can he do in 20

Anon25 [30]

Answer:

baila como juana la cubana

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Building Bonds puts on team-building events. The company charges a base rate of $45 per event, plus $7.50 per participant. Write

expeople1 [14]

Answer:

45+7.50x= y

Step-by-step explanation:

5 0

3 years ago

Help please! I don't really understand :/

hram777 [196]

So you take 2 hours and multiply it by 5 cause you get $5 per hour. Then multiply 6.25 by 5. Add those together to get your answer!! So 5x2= 10. 6.25x5= 31.25. THE ANSWER SHOULD BE 41.25!

4 0

2 years ago

Find the integer that makes this subtraction statement true -3 - ? = -5

Elenna [48]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{2}}}}}$

Step-by-step explanation:

Let the missing integer be x

Solve for x

$\sf{ - 3 - x = - 5}$

Move 3 to right hand side and change it's sign

$\dashrightarrow{ \sf{ - x = - 5 + 3}}$

The negative and positive integers are always subtracted but posses the sign of the bigger integer

$\dashrightarrow{ \sf{ - x = - 2}}$

Change the signs of both sides

$\dashrightarrow{ \boxed{ \sf{x = 2}}}$

Hope I helped!

Best regards! :D

7 0

3 years ago

john and ted have a reputation of being late to events. If john is late 20% of the time and ted is late 40% of the time what is

oee [108]

Answer:

The probability that they will both be on time is 12/25.

Step-by-step explanation:

John is late 20% of the time.

So, he is prompt 80% of the time.

Ted is late 40% of the time.

So, he is prompt 60% of the time.

Since, both the events are independent,

p(John be on time ∩ Ted be on time) = p(John be on time) × p(Ted be on time)

$= \frac{80}{100}$ × $\frac{60}{100}$

= 0.80 × 0.60

= 0.48 or 48%

$=\frac{12}{25}$

Hence, the probability that they will both be on time is 12/25.

3 0

3 years ago