First you are going to look at the smallest box and figure out what the area is once you do that you will need to find the area of the bigger box once you figure out both of the areas you will then find out what they are you will then add up the amounts to get the area of both squares together
Solve the top equation to get on variable on one side
2x-y=6
-y=-2x+6
y=2x-6
then plug in the coordinate for x and y for both equations. if both equations are true then it’s a solution
2=2(2)+6
2=10
4+2=6
so it’s not a solution
Answer:
The answer is c
Step-by-step explanation:
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The length and width of the rug is 20 and 11 feet respectively
The given parameters;
dimension of the room = 19 ft by 28 ft
maximum area of rug she can afford = 220 ft²
For a uniform stripe of floor around the rug, then suppose the uniform excess length of the floor to removed from each dimension = y
(28-2x)(19-2x)=220
532-94x+4x^2=220
4x^2-94x+312=0
x=39/2,4
For x=39/2, dimensions are negative.
The uniform dimension of the floor to be covered by the maximum area of rug she can afford = (28 - 4×2) and (19 -2×4 ) = 20 and 11
Thus, the dimensions of the rug should be 20 feet and 11 feet
- The area of a rectangle is length times breadth.
- Area is the total squares cm occupied by a closed figure.
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4x40= 160
6x40= 240
160/12= 13.33
240/12= 20
13.33x20= 266.6
The answer is 266.6 square feet
