i. 171
ii. 162
iii. 297
Solution,
n(U)= 630
n(I)= 333
n(T)= 168
i. Let n(I intersection T ) be X
<h3>ii.
n(only I)= n(I) - n(I intersection T)</h3><h3>
= 333 - 171</h3><h3>
= 162</h3>
<h3>
iii. n ( only T)= n( T) - n( I intersection T)</h3><h3>
= 468 - 171</h3><h3>
= 297</h3>
<h3>
Venn- diagram is shown in the attached picture.</h3>
Hope this helps...
Good luck on your assignment...
Answer:
a number plus 14
fourteen more than a number
a number increased by 14
Step-by-step explanation:
The phrases which can be represented by the algebraic expression x + 14 are
Let x = the unknown number
a number plus 14
= x + 14
fourteen more than a number
= x + 14
a number increased by 14
x + 14
You have to check f(1) in each one to see if it's right and for f(4)
Answer:
f(x) = -(x-4)^2 + 5
Step-by-step explanation:
The function 
is a quadratic function. Its graph looks like a parabola. The graph has a vertex of (4,5) and opens up downward.
Proving that 
for all x:
