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andre [41]
2 years ago
7

If a plane can climb at 2,400 feet per minute, how many minutes are needed to climb to 60,000 feet?

Mathematics
1 answer:
cestrela7 [59]2 years ago
3 0

Hi there --

If a plane can climb 2,400 feet per minute, it will need 25 minutes to reach 60,000 feet. // By dividing 60,000 (the needed feet) by 2,400 (the amount of feet the plane can climb per/min) you get 25 (the amount of mins needed to climb 60,000 feet)

Hope this helps! Have a great day! :)

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A homeowner has an octagonal gazebo inside a circular area. Each vertex of the gazebo lies on the circumference of the circular
Tcecarenko [31]

If we draw the diagonals of the octagonal gazebo, the 4 diagonals divide the octagon into 8 triangles.

Note that each triangle is an isosceles triangle whose equal sides are x, the radius of the circle.

The top angle of each triangle is obtained by dividing the full angle by 8.

So, each top angle = \frac{360}{8}

= 45°

Now, in fig., consider one of the triangles Δ OAB. Draw an altitude OC from O to the opposite side AB.

This altitude OC bisects the top angle 45°.

Therefore, ∠ AOC = 22.5°.

Now, in Δ AOC,

sin 22.5=\frac{AC}{OA}

=\frac{AC}{x}

So, AC = x sin 22.5°

Note that, AB = 2 AC.

Therefore, AB = 2x sin 22.5°.

Also, cos 22.5=\frac{OC}{OA}

=\frac{OC}{x}

So, OC = x cos 22.5°.

Area of Δ AOB = \frac{1}{2}(AB)(OC)

= \frac{1}{2} × (2x sin 22.5°) × (x cos 22.5°)

= \frac{1}{2} x^{2} (2 sin 22.5° cos 22.5°)

= \frac{1}{2} x^{2} sin 45°

= x^{2} / 2\sqrt{2}

Area of the octagonal gazebo = 8 × one triangular area

= 8 × (x^{2} / 2\sqrt{2})

=2\sqrt{2} x^{2}

=2.828x^{2}

Area required for mulch = circular area - area of the gazebo

=3.14x^{2} -2.828x^{2}

=0.312x^{2}

Now, cost per unit area = $1.50.

Hence, total cost g(m) = area × cost per unit area

Total cost g(m) = 0.312x^{2} × 1.5

=0.468x^{2}

Hence, total cost g(m) = 0.468x^{2}.

4 0
3 years ago
A stone is thrown vertically upward from a platform that is 20 feet height at a rate of 160 ft/sec. Use the quadratic function h
Nutka1998 [239]

Check the picture below.

\textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{-16}x^2\stackrel{\stackrel{b}{\downarrow }}{+160}x\stackrel{\stackrel{c}{\downarrow }}{+20} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right)

\left(-\cfrac{ 160}{2(-16)}~~~~ ,~~~~ 20-\cfrac{ (160)^2}{4(-16)}\right) \implies \left( - \cfrac{ 160 }{ -32 }~~,~~20 - \cfrac{ 25600 }{ -64 } \right) \\\\\\ \left( 5 ~~~~ ,~~~~ 20 +400 \right)\implies (\stackrel{seconds}{5}~~,~~\stackrel{feet}{420})

6 0
1 year ago
Delana also bought 3 bags of pencils with 12 pencils in each bag.When the party began, she found that 13 of the pencils were bro
Ymorist [56]

Answer:

20

Step-by-step explanation:

3*12=36-13=20

5 0
2 years ago
From a boat on the lake, the angle of elevation to the top of a cliff is 26°1'. If the base of the cliff is 205 feet from the bo
Zolol [24]
We use the tangent for this

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7 0
3 years ago
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gayaneshka [121]

Answer:

C. 7.8

Step-by-step explanation:

This problem involves the use of a trigonometric ratio. This one specifically involves the use of cosine as it provides the leg adjacent to the angle and the hypotenuse.

cos(40) = 6/x

cos(40)*x=6/x*x

cos(40)*x=6

cos(40)/cos(40)*x=6/cos(40)

x=6/cos(40)

x=7.83

The value of x is C. 7.8

4 0
2 years ago
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