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valina [46]
3 years ago
15

Find the interquartile range for the data set 10,3,8,9,12,,13.

Mathematics
1 answer:
cluponka [151]3 years ago
7 0
I think it is 8 but im not sure(sorry if its wrong)
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55 POINTS ASAP
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Step-by-step explanation:

Option B. Here Adam Ct. is perpendicular to Betha Dr. and Charles. So, St. Bertha Dr. || Charles St. Since they are parallel to each other

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Help with this math please ​
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Step-by-step explanation:

5 0
3 years ago
Simplify the rational expression. State any restrictions on the variable.
ExtremeBDS [4]

we are given

\frac{(n^4-10n^2+24)}{(n^4-9n^2+18)}

Firstly, we will factor numerators and denominators

\frac{(n^4-10n^2+24)}{(n^4-9n^2+18)}=\frac{(n^2-6)(n^2-4)}{(n^2-3)(n^2-6)}

we can see that

n^2 -6 is factor on both numerator and denominator

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n^2-6\neq 0

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3 years ago
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A line parallel to the y-axis that passes through (77,88) is x = 77.  There is no slope-intercept form of this equation if our coordinate system is based upon a horizontal x-axis and a vertical y-axis.

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GuDViN [60]

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To get a 15 in the denominator of 1/3, we multiply the numerator and the denominator by 5 which gives us 5/15.

To get a 15 in the denominator of 3/5, we multiply the numerator and the denominator by 3 which gives us 9/15.

Notice that we now have like fractions since both fractions have a 15 in the denominator.

To compare like fractions, we simply look at the numerators.

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Since 9 is greater than 5, 9/15 is greater than 5/15.

This means that 3/5 is bigger than 1/3.

3 0
3 years ago
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