Answer:
1
Step-by-step explanation:
If P(E) = p
Then P(not E) = 1-p
Step-by-step explanation:
Hey, there!
As it is a Right angled triangle, taking reference angle as angle B.
hypotenuse (h)= AB
perpendicular (p)= 12
base (b)= 24.
Now, let's look which ratio can be used here as p and b are given. Let's use tan ratio here.( as tan = p/b)
![\tan(theta) = \frac{p}{b}](https://tex.z-dn.net/?f=%20%5Ctan%28theta%29%20%20%3D%20%20%5Cfrac%7Bp%7D%7Bb%7D%20)
![tan(theta) = \frac{12}{24}](https://tex.z-dn.net/?f=tan%28theta%29%20%3D%20%20%5Cfrac%7B12%7D%7B24%7D%20)
![\tan(theta) = \frac{1}{2}](https://tex.z-dn.net/?f=%20%5Ctan%28theta%29%20%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20)
or, tan theta = (0.5)
Shifting tan to right side making it inverse.
or, theta = tan inverse (0.5)
Therefore, theta = 26.56° or 27° { by rounding off 26.56° we get 27°}.
<em>Hope it helps</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>
Answer:
The volume of the square pyramid is ![80\ cm^{3}](https://tex.z-dn.net/?f=80%5C%20cm%5E%7B3%7D)
Step-by-step explanation:
we know that
The volume of a pyramid is equal to
![V=\frac{1}{3}Bh](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7DBh)
where
B is the area of the base of pyramid
h is the height of the pyramid
in this problem we have
![B=16\ cm^{2}](https://tex.z-dn.net/?f=B%3D16%5C%20cm%5E%7B2%7D)
![h=15\ cm^{2}](https://tex.z-dn.net/?f=h%3D15%5C%20cm%5E%7B2%7D)
substitute the values
![V=\frac{1}{3}(16)(15)=80\ cm^{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7D%2816%29%2815%29%3D80%5C%20cm%5E%7B3%7D)
Class I
Trailer hitches are divided into different classes on the basis of the weight that they will be supporting. The classes are Class I - V, after which the classes are Xtra Duty and finally the Commercial Duty class, which has the ability to support 20,000 lbs.