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3 years ago

Find the secant of both angle A and angle B.

Mathematics

1 answer:

Harlamova29_29 [7]3 years ago

7 0

The secant of an angle is <span>the ratio of the hypotenuse to the shorter side adjacent to an acute angle. It is the reciprocal of cosine function. Therefore, the correct answer from the choices is option B.

sec A = 26/24 =13/12
sec B = 26/10 = 13/5
</span>

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3 years ago

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Find x and y in the figure

Grace [21]

Answer:

x=10, y=25

Step-by-step explanation:

First, in a trapezoid, the two angles on the same leg (the legs are the opposite sides that are not parallel) add up to 180 degrees. Therefore, 4y as well as (2y+3x) are supplementary. We can write this out as

4y + (2y+3x) = 180

6y+3x = 180

Next, the angles of a triangle add up to 180 degrees. Therefore, as the angles 2y, 4y, and (5x-20) make up a triangle, they add up to 180 degrees. We can write this as

4y + 2y + (5x-20) = 180

6y + 5x -20 =180

Our two equations are thus

6y + 5x - 20 = 180

6y + 3x = 180

If we subtract 6y from both sides in each equation, we can say

5x - 20 = 180-6y

3x = 180-6y

Therefore, we can write

5x-20 = 180-5y = 3x

5x-20=3x

subtract 3x from both sides to make all x variables on the same side

2x-20 = 0

add 20 to both sides to isolate the x and its coefficient

2x = 20

divide both sides by 2 to isolate x

x = 10

Therefore,

x = 10

6y + 3x = 180

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subtract 30 from both sides to isolate the y and its coefficient

6y = 150

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5 0

3 years ago

Directions: Calculate the area of a circle using 3.14x the radius

Leokris [45]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

As we know ~

Area of the circle is :

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

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<h3>Problem 1</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 4.4\div 2$

$\qquad \sf \dashrightarrow \:r = 2.2 \: mm$

Now find the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(2.2)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {4.84}^{}$

$\qquad \sf \dashrightarrow \:area \approx 15.2 \: \: mm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 2</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 3.7 \div 2$

$\qquad \sf \dashrightarrow \:r = 1.85 \: \: cm$

Bow, calculate the Area ~

$\qquad \sf \dashrightarrow \: \pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (1.85) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 3.4225 {}^{}$

$\qquad \sf \dashrightarrow \:area \approx 10.75 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 3 </h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (8.3) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 68.89$

$\qquad \sf \dashrightarrow \:area \approx216.31 \: \: cm {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>Problem 4</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 5.8 \div 2$

$\qquad \sf \dashrightarrow \:r = 2.9 \: \: yd$

now, let's calculate area ~

$\qquad \sf \dashrightarrow \:3.14 \times {(2.9)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 8.41$

$\qquad \sf \dashrightarrow \:area \approx26.41 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 5</h3>

$\qquad \sf \dashrightarrow \:r = d \div 2$

$\qquad \sf \dashrightarrow \:r = 1 \div 2$

$\qquad \sf \dashrightarrow \:r = 0.5 \: \: yd$

Now, let's calculate area ~

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times (0.5) {}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 0.25$

$\qquad \sf \dashrightarrow \:area \approx0.785 \: \: yd {}^{2}$

・．━━━━━━━†━━━━━━━━━．・

<h3>problem 6</h3>

$\qquad \sf \dashrightarrow \:\pi {r}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times {(8)}^{2}$

$\qquad \sf \dashrightarrow \:3.14 \times 64$

$\qquad \sf \dashrightarrow \:area = 200.96 \: \: yd {}^{2}$

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8 0

2 years ago

The claim is that the proportion of accidental deaths of the elderly attributable to residential falls is more than 0.10, and th

Alex777 [14]

Answer:

The correct option is b) 4.71

Step-by-step explanation:

Consider the provided information.

Test statistic for proportion: $z=\frac{\hat p-p}{\sqrt{\frac{pq}{n}}}$

It is given that the claim is that the proportion of accidental deaths of the elderly attributable to residential falls is more than 0.10, and the sample statistics include n=800 deaths of the elderly with 15 percent of them attribute to residential falls.

Therefore, $\hat p=0.15$ , p = 0.1, q = 1-0.1 = 0.9 and n = 800.

Substitute the respective values in the above formula.

$z=\frac{0.15-0.1}{\sqrt{\frac{0.1\times0.9}{800}}}$

$z=\frac{0.05}{\sqrt{\frac{0.09}{800}}}$

$z\approx4.71$

Hence, the correct option is b) 4.71

3 0

3 years ago