Answer:
From the photo above i interpreted the question and drew a triangle to make it easier to solve
Tan is used to solve the question as we were given opposite (as height of the cliff) and to find Adjacent ( the distance between the foot of the cliff to the boat)
Tan θ =Opp/Adj
Tan 22°=15/a
Cross Multiply
aTanθ=15°
Divide both sides by Tan 22
aTan22/Tan22 = 15/Tan 22
a = 15/Tan 22°
a = 37.13 m
Therefore the distance between the foot of the cliff to the boat is 37.13 metres
Answer:
arcLP = 19
Step-by-step explanation:
Given the following
arcLM = 8x-56
arcNP = 5x+22
Required
arcLP
Given that arcLM = arcNP
8x-56 = 5x+22
8x - 5x = 22 + 56
3x = 78
x = 78/3
x = 26
Let assume arcLP = x - 7
arcLP = 26 -7
arcLP = 19
Answer:
y+6=2(x-3)
Step-by-step explanation:
y-y1=m(x-x1)
y-(-6)=2(x-3)
y+6=2(x-3)
Answer:
16 yd. This is the park's actual length.
Step-by-step explanation:
Write and solve an equation of ratios:
1 1/4 cm 8 yd
------------ = -----------
2 1/2 cm x
Note that 2(1 1/4 cm) = 2 1/2 cm, so the above equation becomes:
1 8 yd
----- = ---------
2 x
Solving for x, we get x = 16 yd. This is the park's actual length.
