Answer:
m<0 = 50
Step-by-step explanation:
The opposite angles in an isosceles trapezoid are equal, so <T = <A
and <B = <O
We know the sum of all 4 angles has to be 360 since it is a quadrilateral
<T+<A + < B + <O = 360
Substituting what we know, and what we want to know
<T+ <T + <O <+O = 360
Combining like terms
2<T + 2 <0 = 360
2( 130) + 2<0 = 360
260 + 2< O = 360
Subtract 260 from each side
260-260 + 2< O = 360-260
2<O = 100
Divide by 2
2/2<O = 100/2
<0 = 50
Answer:
m∠MNQ = 158
Step-by-step explanation:
As it can be seen in the figure:
+) The measure of arc MQ = 91 degree
+) The measure of arc RP = 225 degree
As this is the circle, four points M, Q, P and R are on the circle, so that we have:
+) m∠RMP = 1/2. measure of arc RP = 1/2 x 225 = 112.5 degree
As N is on MP
=> m∠RMN = m∠RMP = 112.5
+) m∠ MRQ = 1/2 measure of arc MQ = 1/2 x 91 = 45.5 degree
As N is on RQ
=> m∠MRN = m∠MRQ = 45.5
In the triangle RMN, the total measure of 3 internal angles is equal to 180 degree, so that:
m∠MNR + m∠RMN + m∠MRN = 180
=> m∠MNR + 112.5 + 45.5 = 180
=> m∠MNR = 180 -112.5 -45.5 = 22
As N is on QR
=> m∠MNR + m∠MNQ = 180
=> m∠MNQ = 180 - m∠MNR = 180 - 22 = 158
So that m∠MNQ = 158
Answer:
I KNOW IT I HAD IT LAST YEAR
Step-by-step explanation:
Answer:
41.8°
Step-by-step explanation:
We solve using the Trigonometric function of Sine
Hypotenuse = 15cm
x = θ
Opposite = 10cm
sin θ = Opposite/Hypotenuse
sin θ = 10/15
θ = arc sin ( 10/15)
θ = 41.810314896°
θ = Approximately to 1 decimal place = 41.8°
Therefore, x = θ = 41.8°
Answer: Linear pair is a pair of two supplementary angles. But two supplementary angles might or might not form a linear pair, they just have to "supplement" each other, that is their sum should be 180°, thus the Answer is B: Sometimes
