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harina [27]
3 years ago
10

Please help me with this question

Mathematics
2 answers:
BartSMP [9]3 years ago
5 0
It’s the first one plug it in
spin [16.1K]3 years ago
3 0

Answer: the first option, 2(x-3)=22

Step-by-step explanation: 14-3=11    11x2=22

You might be interested in
Y<br> 45°<br> X 100°<br> y = [ ? 1°
deff fn [24]

Step-by-step explanation:

x+100°=180°{being straight angle}

x=180-100

x=80°

again,

45°+x+y=180°{sum of angle of triangle}

45+80+y=180

y=180-125°

y=55°

hope it helps.

8 0
3 years ago
PLEASE HELP ME ANSWER! im so desperate bro !!
sergey [27]

a)13

b) skewed

c) IQR

d)Sam's observation is correct

e)6.17

Step-by-step explanation:

Step 1 :

From the histogram we can infer that

0 to 2 texts has been sent by 1 student

2 to 4 texts has been sent by 3 student

4 to 6 texts has been sent by 4 student

6 to 8 texts has been sent by 4 student

8 to 10 texts has been sent by 5 student

Step 2:

a)

From step 1 , we can see that there are total of 17 students represented by the histogram

Step 3:

b)

This is a skewed histogram because we have all large values of students on the right of the histogram and smaller values on the left of the histogram.

In symmetrical histogram, there would be large values on the center and the smaller values on both sides.

Step 4:

c)

IQR would be better recommendation for this as this is a skewed histogram

Standard deviation would be recommended for a symmetrical histogram

Step 5:

d)

Total number of students is 17

Number of students who text between 8 to 10 messages is 5

Hence the students who text between 8 and 10 messages is 5/17

which is nearly 1/3 rd of the total students.

Hence Sam's observation is correct

Step 6:

e)

Mean amount of the texts = (1 * 3 + 3* 3 + 5*4 +7*4 + 9* 5) /17 = 6.17

6 0
3 years ago
The response to a question has three alternatives: A, B, and C. A sample of 120 responses provides 60 A, 12 B, and 48 C. Show th
zimovet [89]

Answer:

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

Step-by-step explanation:

Given that;

the frequencies of there alternatives are;

Frequency A = 60

Frequency B = 12

Frequency C = 48

Total = 60 + 12 + 48 = 120

Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;

Relative Frequency A = Frequency A / total = 60 / 120 = 0.5

Relative Frequency B = Frequency B / total = 12 / 120 = 0.1

Relative Frequency C = Frequency C / total = 48 / 120 = 0.4

therefore;

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

5 0
2 years ago
Find the sum. Enter your answer in the box.<br><br> 3 + (–4)
Bess [88]

Answer:

the answer is -1

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
ty rode his trail bike for 4.5 hours. his average speed was 12 miles per hour. how many miles did he ride?
Viefleur [7K]
Hey there!


Ty rode is bike 54 miles.

Work:
4.5 x 12


Hope this helps!
5 0
3 years ago
Read 2 more answers
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