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3 years ago

6

Help me solve these please

1 answer:

Burka [1]3 years ago

4 0

<span>______________________________________________________</span>
7y-1=-1+9(y-9)
Add 1 on both sides.
7y=9(y-9)
Distribute.
7y=9y-81
Subtract 7y and add 81 on both sides.
2y=81
y=40.5
______________________________________________________

<span>4c+3=-12+c-1
</span>Subtract 3 on both sides.
4c=-12-1-3+c
Subtract c on both sides.
3c=-16
c=-16/3
______________________________________________________
<span>-(k+1)-10=-5k+3
</span>Add 10 on both sides.
-(k+1)=-5k+13
Distribute.
-k-1=-5k+13
Add 1 and add 5k on both sides.
4k=14
k=4/14
______________________________________________________
-w-10=-9-2(w-8)
Distribute.
-w-10=-9-2w+16
Simplify.
-w-10=-2w+7
Add 2w and 10 on both sides.
w=17
______________________________________________________
-2(n-3)-5=-5n+1
Distribute.
-2n+6-5=-5n+1
Simplify.
-2n+1=-5n+1
Add 5n and subtract 1 on both sides.
3n=0
n=0
______________________________________________________

To make sure you got the right answer, you can check your work by plugging the result back into the question and seeing if both sides become equal. If both sides are equal, then the result is correct.
______________________________________________________

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AfilCa [17]

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a) The trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.

b) At that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

Step-by-step explanation:

a) First, we need to find the distance traveled by the cargo train in the two hours before the passenger train leaves Chicago:

$x_{1} = v_{1}t_{1} = 120 km/h*2h = 240 km$

Now, we can find the time when the trains will be 1520 km apart:

$1520 km = (x_{1} + 240 km) + x_{2}$

Where 1 is for the cargo train and 2 is for the passenger train.

$1520 km = (v_{1}*t_{1} + 240 km) + v_{2}t_{2}$

Since we need to calculate the time when the trains are 1520 km apart, t₁ = t₂, so:

$1520 km = (v_{1}*t + 240 km) + v_{2}t$

$t = \frac{1520 km - 240 km}{120 km/h + 360 km/h} = 2.667h$

For the cargo train, it will be 1520 km apart from the passenger train at:

$t_{1} = 12 pm + 2 h + 40 min = 2:40 pm$

And for a passenger train, it will be 1520 km apart from the cargo train at:

$t_{2} = 2 pm + 2 h + 40 min = 4:40 pm$

Hence, the trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.

b) The distance traveled by both trains is given by:

$x_{1} = v_{1}*t + 240 km = 120 km/h*2.667 h + 240 km = 560.04 km$

$x_{2} = v_{2}*t = 360 km/h*2.667 h = 960.12 km$

Therefore, at that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

I hope it helps you!

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