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3 years ago

Lucy is tiling her bathroom. She buys white and blue tiles in the

Mathematics

1 answer:

balandron [24]3 years ago

7 0

Answer:

£289.20

Step-by-step explanation:

13:2 = x:16 or 13/2 = x/16

cross multiply: 208 = 2x

simplify: x = 104

16 blue tiles x £2.80 each = £44.80

104 white tiles x £2.35 each = £244.40

44.80 + 244.40 = £289.20

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create a ratio table for making lemonade with a lemon juice -to -water ratio of 1:3 show how much lemon juice would be needed if

Mekhanik [1.2K]

The ratio is 12:36 of lemonade juice to water so 1:3, 2:6, 3:9 and so on.

6 0

3 years ago

Trever Goetz is a salesperson who is paid a monthly salary of $500 plus a 2% commission on sales. How much must he sell to earn

dedylja [7]

Whatever% of anything is just (whatever/100) * anything.

now, we know Trever makes $500 in salary and 2% on sales, let's say he sells "x" amount, how much is 2% of x? well (2/100) * x, or 0.02x.

Therefore Trever's earnings are 500 + 0.02x, his salary plus his commission.

to earn a total of 2,000, then 500 + 0.02x = 2000, thus

$\bf 500+0.02x=2000\implies 0.02x=1500\implies x=\cfrac{1500}{0.02}\\\\\\ x=75000$

4 0

3 years ago

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using factorization method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using factorization method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. HCF is $2y^{2} (y+ 10)$ .

We know the relation between LCM, HCF of the two numbers 'p' , 'q' and the numbers themselves as:

$HCF \times LCM = p \times q$

Using equations (1) and (2): $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$