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KengaRu [80]
2 years ago
6

write a two-step equation that involves multiplication and subtraction, includes a negative coefficient, and has a solution of x

=7
Mathematics
2 answers:
BigorU [14]2 years ago
7 0

Answer:

<em>Hence, the equation is:</em>

-3x-7=-28

<em>and the solution is:</em>

3x=28-7\\\\3x=21\\\\x=7

Step-by-step explanation:

A two step equation is a equation that takes just two steps to solve.

Now we have to formulate a  two-step equation that involves multiplication and subtraction, includes a negative coefficient, and has a solution of x=7.

negative coefficient means that the coefficient of the variable term must be negative.

so, we take a equation as:

-3x-7=-28

Clearly the coefficient of variable term is: -3 which is negative.

Now we solve the equation as:

3x=28-7\\\\3x=21\\\\x=7

Hence, the equation is:

-3x-7=-28

Mnenie [13.5K]2 years ago
3 0
-60x+20 = -400
x equals 7
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List from least to greatest 0.25,3/8,5/16
marta [7]
---------------------------------------------
Present the numbers in decimal
---------------------------------------------
0.25  = 0.25
3/8 = 0.375
5/16 = 0.3125

<span><em>(It is easier to arrange the number using decimals)</em>
</span>
---------------------------------------------
Arrange the numbers
---------------------------------------------

0.25 (0.25) , 0.3125 (5/16) , 0.0375 (3/8)

<em>(Put the original numbers given in your final answer)</em>

---------------------------------------------
Answer: 0.25 , 5/16 , 3/8
---------------------------------------------
6 0
3 years ago
Lim x-&gt; vô cùng ((căn bậc ba 3 (3x^3+3x^2+x-1)) -(căn bậc 3 (3x^3-x^2+1)))
NNADVOKAT [17]

I believe the given limit is

\displaystyle \lim_{x\to\infty} \bigg(\sqrt[3]{3x^3+3x^2+x-1} - \sqrt[3]{3x^3-x^2+1}\bigg)

Let

a = 3x^3+3x^2+x-1 \text{ and }b = 3x^3-x^2+1

Now rewrite the expression as a difference of cubes:

a^{1/3}-b^{1/3} = \dfrac{\left(a^{1/3}-b^{1/3}\right)\left(a^{2/3}+a^{1/3}b^{1/3}+b^{2/3}\right)}{\left(a^{2/3}+a^{1/3}b^{1/3}+b^{2/3}\right)} \\\\ = \dfrac{a-b}{a^{2/3}+a^{1/3}b^{1/3}+b^{2/3}}

Then

a-b = (3x^3+3x^2+x-1) - (3x^3-x^2+1) \\\\ = 4x^2+x-2

The limit is then equivalent to

\displaystyle \lim_{x\to\infty} \frac{4x^2+x-2}{a^{2/3}+(ab)^{1/3}+b^{2/3}}

From each remaining cube root expression, remove the cubic terms:

a^{2/3} = \left(3x^3+3x^2+x-1\right)^{2/3} \\\\ = \left(x^3\right)^{2/3} \left(3+\dfrac3x+\dfrac1{x^2}-\dfrac1{x^3}\right)^{2/3} \\\\ = x^2 \left(3+\dfrac3x+\dfrac1{x^2}-\dfrac1{x^3}\right)^{2/3}

(ab)^{1/3} = \left((3x^3+3x^2+x-1)(3x^3-x^2+1)\right)^{1/3} \\\\ = \left(\left(x^3\right)^{1/3}\right)^2 \left(\left(3+\dfrac3x+\dfrac1{x^2}-\dfrac1x\right)\left(3-\dfrac1x+\dfrac1{x^3}\right)\right)^{1/3} \\\\ = x^2 \left(9+\dfrac6x-\dfrac1{x^3}+\dfrac4{x^4}+\dfrac1{x^5}-\dfrac1{x^6}\right)^{1/3}

b^{2/3} = \left(3x^3-x^2+1\right)^{2/3} \\\\ = \left(x^3\right)^{2/3} \left(3-\dfrac1x+\dfrac1{x^3}\right)^{2/3} \\\\ = x^2 \left(3-\dfrac1x+\dfrac1{x^3}\right)^{2/3}

Now that we see each term in the denominator has a factor of <em>x</em> ², we can eliminate it :

\displaystyle \lim_{x\to\infty} \frac{4x^2+x-2}{a^{2/3}+(ab)^{1/3}+b^{2/3}} \\\\ = \lim_{x\to\infty} \frac{4x^2+x-2}{x^2 \left(\left(3+\dfrac3x+\dfrac1{x^2}-\dfrac1{x^3}\right)^{2/3} + \left(9+\dfrac6x-\dfrac1{x^3}+\dfrac4{x^4}+\dfrac1{x^5}-\dfrac1{x^6}\right)^{1/3} + \left(3-\dfrac1x+\dfrac1{x^3}\right)^{2/3}\right)}

=\displaystyle \lim_{x\to\infty} \frac{4+\dfrac1x-\dfrac2{x^2}}{\left(3+\dfrac3x+\dfrac1{x^2}-\dfrac1{x^3}\right)^{2/3} + \left(9+\dfrac6x-\dfrac1{x^3}+\dfrac4{x^4}+\dfrac1{x^5}-\dfrac1{x^6}\right)^{1/3} + \left(3-\dfrac1x+\dfrac1{x^3}\right)^{2/3}}

As <em>x</em> goes to infinity, each of the 1/<em>x</em> ⁿ terms converge to 0, leaving us with the overall limit,

\displaystyle \frac{4+0-0}{(3+0+0-0)^{2/3} + (9+0-0+0+0-0)^{1/3} + (3-0+0)^{2/3}} \\\\ = \frac{4}{3^{2/3}+(3^2)^{1/3}+3^{2/3}} \\\\ = \frac{4}{3\cdot 3^{2/3}} = \boxed{\frac{4}{3^{5/3}}}

8 0
3 years ago
This is 10 points, PLS help
algol [13]

Answer:

Sound can travel 12 miles per minute.

Step-by-step explanation:

Speed equation is distance divided by time.

So we have 1 mile per 1/12 of a minute.

Let’s write the equation.

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1 * 12 = 12.

3 0
3 years ago
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elena-s [515]
First, substitute 4 into x
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5 0
3 years ago
Read 2 more answers
If the angles are represented in degrees, find both angles:<br> cos(8x+18)=sin(−2x+36)
larisa [96]

Answer:

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Step-by-step explanation:

Given the equation

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The given expression becomes;

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sin will cancel out to have;

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90-8x-18 = -2x+36

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x = 36/6

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= cos  66

Also

sin(−2x+36)

= sin(−2(6)+36)

= sin(−12+36)

= sin 24

Hence both angles are 24 and 66degrees

7 0
3 years ago
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