Answer:
1) yes
2) no
3. yes
Step-by-step explanation:
(plz make me brainliest)
Answer:
b. 144.8
Step-by-step explanation:
When calculating the moving average estimate of an observation , each of the observations are usually computed with the same weighted . In some cases, it is beneficial to assign different weight on the observations such that the observation closer to the time period being forecast, has higher weight. This is refer to as weighted moving average technique. The sum of the individual weight in a weighted moving average technique must equal to 1.
The three-period weighted moving average forecast for period 5 = 144*0.5 + 148 *0.3 + 142 *0.2 = 144.8
Answer:
4x - 2
Step-by-step explanation:
3(2x - 2) - 2(x - 2) [Distributive Property]
6x - 6 - 2x + 4
4x - 2
Answer:
C. 303,000 Joules
Step-by-step explanation:
1. use abcos(theta)
a=50
b=7000
theta=30 degrees
2. (50)(7000)cos(30)=303,000
