The answer is 1.7m because 0.9 isnt bigger
Answer:
The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction
Step-by-step explanation:
- For a constant acceleration: , where is the final velocity in a direction after the acceleration is applied, is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
- <em>Then for the x direction</em> it is known that the initial velocity is 5320 m/s, the acceleration (the applied by the engine) in x direction is 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then:
- In the same fashion, <em>for the y direction</em>, the initial velocity is 0 m/s, the acceleration in y direction is 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction:
Answer:
98
Step-by-step explanation:
180- 122 = 58
58 + 24= 82
180- 82= 98
Answer: -1/6
Step-by-step explanation:I’ve taken the test