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marusya05 [52]
3 years ago
6

Divide the number 20 into two parts (not necessarily integers) in a way that makes the product of one part with the square of th

e other as large as possible
use calculus methods
Mathematics
1 answer:
Ilya [14]3 years ago
3 0

Answer:

13 1/3 and  6 2/3.

Step-by-step explanation:

Let the 2 parts be x and (20 - x).

So x^2(20 - x) must be a maximum.

y = x^2(20 - x)

y = 20x^2 - x^3

Finding the derivative):

y' =  40x - 3x^2 = 0   for  maxm/minm value.

x( 40 - 3x) = 0

40 - 3x = 0

3x = 40

x = 40/3.

This is a maximum because the second derivative y" =  40 - 6x = 40 - 6(40/3)) is negative.

So the 2 numbers are 13 1/3 and  6 2/3.

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Find the least common denominators of these two rational experssions -1/y and 2/5y
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In a triangle, two sides that measure 8 centimeters and 11 centimeters form an angle that measures 82°. to the nearest tenth of
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<span>First we must find the third side (АС) of the triangle:
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The smallest angle of the triangle lies opposite the smallest side, so we need to find m</span>∠C.

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<span>I hope this helps</span>

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