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3 years ago

C. 46.97 D. 45.07 Math question don't guess Please help

Mathematics

1 answer:

alexandr402 [8]3 years ago

4 0

sin 51 = BC / 58

BC = 58 sin 51

= 45.07 to nearest hundredth.

Its D

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How do you write 1/8 of q added to 4 as an algebraic expression?

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Answer:

1/8q + 4

Step-by-step explanation:

If you multiply q by 1/8 you will get 1/8 of q. Then you add it to 4.

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2 years ago

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Answer:

The out put 1. 5

The out put 2. 6

Step-by-step explanation:

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Jane must get at least three of the four problems on the exam correct to get an A. She has been able to do 80% of the problems o

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Answer:

a) There is n 81.92% probability that she gets an A.

b) If she gets the first problem correct, there is an 89.6% probability that she gets an A.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the answer is correct, or it is not. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

For this problem, we have that:

The probability she gets any problem correct is 0.8, so $\pi = 0.8$ .

(a) What is the probability she gets an A?

There are four problems, so $n = 4$

Jane must get at least three of the four problems on the exam correct to get an A.

So, we need to find $P(X \geq 3)$

$P(X \geq 3) = P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 3) = C_{4,3}.(0.80)^{3}.(0.2)^{1} = 0.4096$

$P(X = 4) = C_{4,4}.(0.80)^{4}.(0.2)^{0} = 0.4096$

$P(X \geq 3) = P(X = 3) + P(X = 4) = 2*0.4096 = 0.8192$

There is n 81.92% probability that she gets an A.

(b) If she gets the first problem correct, what is the probability she gets an A?

Now, there are only 3 problems left, so $n = 3$

To get an A, she must get at least 2 of them right, since one(the first one) she has already got it correct.

So, we need to find $P(X \geq 2)$

$P(X \geq 3) = P(X = 2) + P(X = 3)$

$P(X = 2) = C_{3,2}.(0.80)^{2}.(0.2)^{1} = 0.384$

$P(X = 4) = C_{3,3}.(0.80)^{3}.(0.2)^{0} = 0.512$

$P(X \geq 3) = P(X = 2) + P(X = 3) = 0.384 + 0.512 = 0.896$

If she gets the first problem correct, there is an 89.6% probability that she gets an A.

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the outdoor temperaturedeclines 3 degrees each hour for 5 hours. What is the change in temperature at the end of those 5 hours?

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15 degrees will be declined in the 5 hours.

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3 years ago

It is a week before the maths festival. A maths exhibitor costs £75.40 and so far 12 have been bought.

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Answer:

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£75.40*12= 904.8£

Step-by-step explanation:

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3 years ago