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storchak [24]
3 years ago
6

Long Division

Mathematics
1 answer:
Elenna [48]3 years ago
7 0

check the picture below.

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Pls pls help with this math
bixtya [17]

Answer:

7, -1

Step-by-step explanation:

x^2 - 6x + 7 = 0

(x - 7)(x + 1) = 0

==> x = 7, x = -1

5 0
3 years ago
Read 2 more answers
Simplify:<br> 3 [23 + (4 – 2)3 – (6 - 2)2]<br> A. 3<br><br> B. 12<br> D. 24<br><br> E-3
diamong [38]

Answer:63

Step-by-step explanation:

4 0
3 years ago
Serenity invested $2,400 in an account paying an interest rate of 3.4% compounded
Alisiya [41]

Answer:

It would take 5.9 years to the nearest tenth of a year

Step-by-step explanation:

The formula of the compound continuously interest is A = Pe^{rt} , where

  • A is the value of the account in t years
  • P is the principal initially invested
  • e is the base of a natural logarithm
  • r is the rate of interest in decimal

∵ Serenity invested $2,400 in an account

∴ P = 2400

∵ The account paying an interest rate of 3.4%, compounded continuously

∴ r = 3.4% ⇒ divide it by 100 to change it to decimal

∴ r = 3.4 ÷ 100 = 0.034

∵ The value of the account reached to $2,930

∴ A = 2930

→ Substitute these values in the formula above to find t

∵ 2930 = 2400e^{0.034t}

→ Divide both sides by 2400

∴ \frac{293}{240} = e^{0.034t}

→ Insert ㏑ in both sides

∴ ㏑(\frac{293}{240}) = ㏑(e^{0.034t})

→ Remember ㏑(e^{n}) = n

∴ ㏑(\frac{293}{240}) = 0.034t

→ Divide both sides by 0.034 to find t

∴ 5.868637814 = t

→ Round it to the nearest tenth of a year

∴ t = 5.9 years

∴ It would take 5.9 years to the nearest tenth of a year

8 0
2 years ago
123<br> 12<br> a<br> d<br> 3<br> and which term are like terms?
Brilliant_brown [7]

Answer:

a and d, and 123, 12 and 3

6 0
3 years ago
Read 2 more answers
Verify cos(x+y)/cos(x-y) = cot(x-y)/cot(x+y)
JulijaS [17]

\bf \cfrac{cos(x+y)}{cos(x-y)}=\cfrac{cot(x-y)}{cot(x+y)} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{expanding the left-hand-side}}{\cfrac{cos(x)cos(y)-sin(x)sin(y)}{cos(x)cos(y)+sin(x)sin(y)}} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{expanding the right-hand-side}}{\cfrac{~~ \frac{cos(x)cos(y)+sin(x)sin(y)}{sin(x)cos(y)-cos(x)sin(y)}~~}{\frac{cos(x)cos(y)-sin(x)sin(y)}{sin(x)cos(y)+cos(x)sin(y)}}} \\\\\\ \cfrac{cos(x)cos(y)+sin(x)sin(y)}{sin(x)cos(y)-cos(x)sin(y)}\cdot \cfrac{sin(x)cos(y)+cos(x)sin(y)}{cos(x)cos(y)-sin(x)sin(y)}

3 0
3 years ago
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