The cross of heterozygous
AaBb as parental phenotype led to formation of 1
6 phenotype of the offspring.This is because this is dihybrid form of inheritance .The probability of having
aabb offspring is
1/16 since there is only one aabb type of offspring phenotype out of
the
16. An illustration of how crossing is done is as per punnet square below
Answer:
If it helps, the answer is Mutualism (let me know if it is for some reason incorrect)
Answer:
a. It's a carrier protein doing facillitated diffusion
Explanation:
Facilitated diffusion may be defined as the transportation of molecules from a high concentration to a low concentration that is down the concentration gradient without input of the energy. Whereas the active transport is transportation of the molecules from the low concentration to the high concentration which is against concentration gradient by the membrane protein.
The glucose transportation process requires membrane protein for the transport and does not require any energy. Therefore, it is carrier protein which is doing the facilitated diffusion.
The first is ture the second false the three is ture 4 ture 5 false 6 ture 7 false 8 ture 9 ture 10 false
