In proving that C is the midpoint of AB, we see truly that C has Symmetric property.
<h3>What is the proof about?</h3>
Note that:
AB = 12
AC = 6.
BC = AB - AC
= 12 - 6
=6
So, AC, BC= 6
Since C is in the middle, one can say that C is the midpoint of AB.
Note that the use of segment addition property shows: AC + CB = AB = 12
Since it has Symmetric property, AC = 6 and Subtraction property shows that CB = 6
Therefore, AC = CB and thus In proving that C is the midpoint of AB, we see truly that C has Symmetric property.
See full question below
Given: AB = 12 AC = 6 Prove: C is the midpoint of AB. A line has points A, C, B. Proof: We are given that AB = 12 and AC = 6. Applying the segment addition property, we get AC + CB = AB. Applying the substitution property, we get 6 + CB = 12. The subtraction property can be used to find CB = 6. The symmetric property shows that 6 = AC. Since CB = 6 and 6 = AC, AC = CB by the property. So, AC ≅ CB by the definition of congruent segments. Finally, C is the midpoint of AB because it divides AB into two congruent segments. Answer choices: Congruence Symmetric Reflexive Transitive
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Answer:
128
Step-by-step explanation:
7×8=56
12×6=72
56+72=128
Answer:
1
Step-by-step explanation:
lowest
Answer:
x = 11
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
sum the 3 angles and equate to 180
5x + 4 + 6x - 3 + 4x + 14 = 180 ← collect like terms on left side
15x + 15 = 180 ( subtract 15 from both sides )
15x = 165 ( divide both sides by 15 )
x = 11
