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Alja [10]
3 years ago
15

In a homicide case 33 different witnesses picked the same man from a line up. the line up contained 5 men. if the identification

s were made by random​ guesses, find the probability that all 33 witnesses would pick the same person. round to seven decimal places.

Mathematics
1 answer:
polet [3.4K]3 years ago
6 0
the correct question in the attached figure
<span>
we know that

</span>the probability
that a witness picks a particular person by chance-----> P=1/5

the probability
that all 7 witnesses would pick the same person-----> P=1/5^7=0.0000128

the answer is the option B 0.0000128

<span>There are a variety of problems in which the number of witnesses change, for example
</span><span>....find the probability that all 9 witnesses would pick the same person

</span>in this case, the probability would be-------> P=1/5^9=0.000000512<span>

</span>

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Option B

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Complex roots occur as conjugate pairs so the third root is -3 - i ( note that the sign changes from + to -).

So in factor form we have:-

(x - 2)(x - (-3 + i))(x - (-3 - i)) = 0    Let's expand the last 2 factors first:-

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Now multiplying by (x - 2):-

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5 0
3 years ago
Find the x-intercept(s) of y = 2x2 - 3x - 5.<br> A) -5 <br> B) 2 1/2, -1<br> C) 3, -5 <br> D) 5, -1
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Answer:

\large\boxed{B)\ 2\frac{1}{2},\ -1}

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x-intercepts are for y = 0.

We have the equation:

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Therefore

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