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crimeas [40]
2 years ago
9

Simplify the expression: 8d+9c+1x3=b

Mathematics
2 answers:
VMariaS [17]2 years ago
6 0

Answer:

b=8d+9c+3

Step-by-step explanation:

Multiply:

1x3=3

Rewrite Equation:

b=8d+9c+3

Hence, the correct answer is b=8d+9c+3

kakasveta [241]2 years ago
3 0

Answer: if you are solving for b it would be b=x^3+9c+8d

Step-by-step explanation:

You might be interested in
48 logs on 6 trucks ​
blagie [28]

Answer:

288 is your answer. 8 is your answer.

Step-by-step explanation:

If you want to know how many logs all together, all you do is multiply.

48 x 6 = 288

288 is your answer.

Or division it is

48/6 = 8

8 is your answer.

6 0
3 years ago
Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1
alexandr1967 [171]

Answer:

a) \simeq 0.3012   b) \simeq 0.0494 c) \simeq 0.2438

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, \frac{1.2}{4}

= 0.3 collisions per  month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

          P(X =x) = \frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}


                                                           for x ∈ N ∪ {0}

                       =  0 otherwise --------------------------------------(1)

here, \lambda = 0.3 collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

         P(X = 0) = \frac{e^{-0.3}\times {\0.3}^{0}}{0!}


                      \simeq 0.7408182207 ------------------------------------(2)

Now, since we are calculating  this for 4 months,

so, P(No collision in 4 month period)

     =0.7408182207^{4}

     \simeq 0.3012  -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

           P(X =1) = \frac{e^{-0.3}\times {\0.3}^{1}}{1!}


                      \simeq 0.2222454662 ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

                =0.2222454662^{2}

                \simeq 0.0494 -----------------------------------------(5)

1 collision in 6 months period means

                                \frac{1}{6} collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6]  (which is to be estimated)

=\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

\simeq 0.6543894283-------------------------------------------(6)

So,

P(1  collision in 6 month period)

  =  0.6543894283^{6}

   \simeq 0.0785267444 ------------------------------------------------(7)

So,

P(No collision in 6 months period)

  = (P(X =0)^{6}

   \simeq 0.1652988882 ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

\simeq  0.2438 ---------------------------------------------(9)          

7 0
3 years ago
AaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaA
Ganezh [65]

Answer:

the answer is

B.Plate

i hope this helps ~_~

4 0
3 years ago
Read 2 more answers
Find the Point where the two lines intersect each other. What are the coordinates of this point?
kompoz [17]

Answer:

B. and D.

Step-by-step explanation:

4 0
3 years ago
Reduce to simplest form -\dfrac{1}{4}-\left(-\dfrac{3}{5}\right)=−
Arturiano [62]
Hehehehe
Hahaha
Eat eat eat ugly ah glad to help
I did the quiz
6 0
3 years ago
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