The image of the arrow is missing, so i have attached it.
Answer:
A_t = 69.5 cm²
Step-by-step explanation:
In a second image attached, I have divided the arrow into triangle and rectangle.
From the second image,
A1 is area of triangle while A2 is area of rectangle
Area of triangle is; A1 = ½bh
Our triangle base is given as 9 cm.
To get the height, we will subtract the rectangle height of 8 cm from the total arrow height.
Thus; height of triangle; h = 11 - 8 = 3cm
Thus;
A1 = ½ × 9 × 3
A1 = 13.5 cm²
Formula for area of rectangle is;
A2 = length × breadth
A2 = 8 × 7
A2 = 56 cm²
Thus, total area of arrow is;
A_t = A1 + A2 = 13.5 + 56
A_t = 69.5 cm²
Answer:
42.9m
Step-by-step explanation:
The topic is on similar triangle
you are comparing triangle MNP with triangle MAB
side AB is similar to NP
side MA is similar to MN
side MB is similar to MP
now MA = MN - AN
= 67.2 - 32
= 35.2m
MA/MN = MB/MP
35.2/67.2 = x/81.9
cross multiply and solve
x = 42.9m
Answer:
a. Compressed f toward the x-axis, and then translated it left 4 units.
Step-by-step explanation:
General equation for this is:
y = a√(x - h) + k
- a is how much it's being compress or stretched
- h is how much it's shifted in the x-direction
- k is how much it's being shifted in the y-direction
We're given:
g(x) = 1/2√(x + 4)
g(x) = 1/2√(x - (-4))
My a-value is 1/2, so the original function f(x) is being compressed by 1/2 toward the x-axis.
My h value is -4 so it's being shifted by 4 units. It's shifted to the left because it's negative.
There is not k-value so nothing is shifted in the y-direction.
The radius of the cylinder will be 
<h3>What will be the radius of the cylinder?</h3>
It is given that
Now we know that
putting values in the formula
Thus the radius of the cylinder will be
To learn more about the Volume of the cylinder follow
brainly.com/question/9554871
9514 1404 393
Explanation:
Here's one way to go at it.
Draw segments AB and CO. Define angles as follows. (The triangles with sides that are radii are all isosceles, so their base angles are congruent.)
x = angle OAB = angle OBA
y = angle OAC = angle OCA
z = angle OBC = angle OCB
Consider the angles at each of the points A, B, C.
At A, we have ...
angle CAB = x + y
At B, we have ...
angle CBA = x + z
At C, we have ...
angle ACB = y + z
The sum of the angles of triangle ABC is 180°, as is the sum of angles in triangle ABO. This gives ...
x + x + ∠AOB = (x+y) +(x+z) +(y+z)
∠AOB = 2(y+z) = 2∠ACB
This shows ∠AOB = 2×∠C, as required.
