here we have 3X to 5 seventh power in radical form
we need write this in radical form we knwo that 
so ![3x^{5/7} =\sqrt[7]{3x^{5}}](https://tex.z-dn.net/?f=%203x%5E%7B5%2F7%7D%20%3D%5Csqrt%5B7%5D%7B3x%5E%7B5%7D%7D%20%20%20)
this will be the radical form .
Answer:
irrational.
Step-by-step explanation:
0.7777... repeats and does not end so it is irrational
Answer:To calculate the standard deviation of those numbers:
1.Work out the Mean (the simple average of the numbers)
2.Then for each number: subtract the Mean and square the result.
3.Then work out the mean of those squared differences.
4.Take the square root of that and we are done!
Step-by-step explanation:
The answer to the question
Answer: If the quadratic equation has real, rational solutions, the quickest way to solve it is often to factorise into the form (px + q)(mx + n), where m, n, p and q are integers. This is especially true where the coefficient of x2 is 1.
Example 1 - Solve x2+7x+12=0
Step-by-step explanation:
that's the only one I remember
