Answer:
Step-by-step explanation:
Part A
xf = xo + vo* t + 1/2 a*t^2 Subtract xo
xf - xo = 0*t + 1/2 a*t^2 multiply by 2
2(xf - xo) = at^2 divide by t^2
2(xf - xo ) / t^2 = a
Part B
Givens
xo =0
vo = 0
a = 10 m/s^2
xf = 120 m
Solution
xf = xo + vo* t + 1/2 a*t^2 Substitute the givens
120 = 0 + 0 + 1/2 * 10 * t^2 Multiply by 2
120*2 = 10* t^2
240 = 10*t^2 Divide by 10
240/10 = t^2
24 = t^2 take the square root of both sides.
√24 = √t^2
t = √24
t = √(2 * 2 * 2 * 3)
t = 2√6
Answer: 6x
Work Shown:
For each step, the logs are all base b. This is to save time and hassle of writing tricky notation of having to write the smaller subscript 'b' multiple times. The first rule to use is that log(x^y) = y*log(x) for any base of a logarithm. The second rule is that 
meaning that the log base of itself is 1
log(b^(6x)) = 6x*log(b) .... pull down exponent using the first rule above
log(b^(6x)) = 6x*1 .... use the second rule mentioned
log(b^(6x)) = 6x
Answer:
f(x) = 2x +1
Step-by-step explanation:
Apparently the ordered pairs are ...
(x, f(x)) = (1, 3), (2, 5), (3, 7), (4, 9)
We note that as x increases by 1, the value of f(x) increases by 2. The difference between f(x) and 2x is 3-2·1 = 1, so we have ...
f(x) -2x = 1
f(x) = 2x +1 . . . . . . add 2x
I would approach the problem like this:
1 oz bottle.............................30cm^3
33 oz bottle.............................xcm^3
in a 33 oz bottle will be x=33*30=990cm^3
density=mm/v
13.6g/cm^3= m/ 990cm^3
m= 13.6 * 990=13464 g
or 13.464 kg in a 33 oz bottle
Answer:
1
Step-by-step explanation:
There can be 0, 1 or infinitely many solutions. 0 if they are parallel and are different lines, 1 if the slopes are different, and infinitely many if they are the same line.
2x - 4y = 8
x + y = 7
Change to y = mx + b
y = (1/2)x - 2
y = -x + 7
The slopes are different so there is 1 solution.
Hope this helps Please mark as brainliest and have a blessed day
