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Sergeu [11.5K]
3 years ago
5

Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary.

Mathematics
1 answer:
aliina [53]3 years ago
4 0
\bf \textit{Law of Cosines}\\ \quad \\
c^2 = {{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)\implies 
c = \sqrt{{{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)}\\\\
-----------------------------\\\\
b = \sqrt{{{ a}}^2+{{ c}}^2-(2{{ a}}{{ c}})cos(B)}
\\\\\\
b=\sqrt{{{ 11}}^2+{{ 18}}^2-2(11\cdot 18)cos(104^o)}
\\\\\\
b\approx 23.25512998582180400481\implies b\approx 23.26

so, "b" rounded up is 23.26, now, we know a = 11 and c = 18

well, to get the area then, let  us use Heron's formula

\bf \textit{Heron's Area formula}\\\\
A=\sqrt{s(s-a)(s-b)(s-c)}\qquad 
\begin{cases}
a=11\\
c=18\\
b\approx 23.26\\\\
s=\cfrac{a+b+c}{2}
\end{cases}
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