Why is the product of two rational numbers always rational?
1 answer:
Answer:
The product of two rational numbers is always rational
Step-by-step explanation:
DEFINITION: a number is said to be rational if and only if it is expressed in p/q form i.e, as a fraction(p/q) where, p,q are integers and now, let a/b and c/d be two rational numbers. the product of them : ac/bd. FACT : if we multiply 2 integers, then the product will be an integer. so, ac and bd are both integers for sure and bd is not zero because none of b or d is zero. therefore, as ac/bd satisfy the definition of a rational number, it is a rational number. hence, we can now generalize that, The product of two rational numbers is always rational.
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Step-by-step explanation:
<span>32.2 - (-15.9) + 10 - 15.9 + 7.8= 50 Work </span>32.2 - (-15.9) = 48.1+10= 58.1 58.1 - 15.9= 42.2 42.2+7.8= 50
To solve using completing square method we proceed as follows: x^2-10x+8=0 x^2-10x=-8 but c=(b/2)^2 c=(10/2)^2=25 thus we can add this in our expression to get x^2-10x+25=8+25 factorizing the LHS we get: (x-5)(x-5)=33 (x-5)^2=33 getting the square roots of both sides we have: x-5=+/-√33 x=5+/-√33
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Step-by-step explanation:
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