The error is that -2 times -5 is 10 not -10. Then carry on from there because that error meant the rest is wrong as well.
Answer:
The given expanded sum of the series is 
Step-by-step explanation:
Given problem can be written as

To find their sums:
Now expanding the series
That is put n=5,6,7,8,9 in the given summation
![\sum\limits_{n=5}^{9}3n+2=[3(5)+2]+[3(6)+2]+[3(7)+2]+[3(8)+2]+[3(9)+2]](https://tex.z-dn.net/?f=%5Csum%5Climits_%7Bn%3D5%7D%5E%7B9%7D3n%2B2%3D%5B3%285%29%2B2%5D%2B%5B3%286%29%2B2%5D%2B%5B3%287%29%2B2%5D%2B%5B3%288%29%2B2%5D%2B%5B3%289%29%2B2%5D)
![=[15+2]+[18+2]+[21+2]+[24+2]+[27+2]](https://tex.z-dn.net/?f=%3D%5B15%2B2%5D%2B%5B18%2B2%5D%2B%5B21%2B2%5D%2B%5B24%2B2%5D%2B%5B27%2B2%5D)
(adding the terms)

Therefore 
Therefore the given sum of the series is 
The given expanded sum of the series is 
Answer:
the weight for an object with a velocity of 12 meters per second is 600 kilograms
Step-by-step explanation:
The linear momentum of an article is : p = mv
Where p = Momentum
m = mass
v = velocity
The velocity is 16 meters per second and the object weighs 450 kilograms
So, 
We are supposed to find the weight for an object with a velocity of 12 meters per second
So, p = 12m
We are given that the linear momentum is a constant when the mass varies inversely of the velocity.
So, 
Hence the weight for an object with a velocity of 12 meters per second is 600 kilograms
Answer:
A. Mean = 9.7 (take all the numbers and divide by 10)
Mode = 12
Range = 5
B. Unsure. Would suggest either Mean - average and can tell when bus is running late or early or Mode - highest and lowest time combined
Yes, the game was fair and no one had a better advantage.