Answer:
The distribution will be approximately normal, with mean 350,000 and standard deviation 25,298.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean 
and standard deviation 
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation 
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Population:
Suppose the selling price of homes is skewed right with a mean of 350,000 and a standard deviation of 160000
Sample of 40
Shape approximately normal
Mean 350000
Standard deviation 
The distribution will be approximately normal, with mean 350,000 and standard deviation 25,298.
Answer:
y=(-5/3)x+29
Step-by-step explanation:
we will use the base formula y=mx+b
In order to be perpendicular, the slope must be the flipped fraction and have the opposite sign, so our m is (-5/3)
y=(-5/3)x+b
You can plug in the (9,14) point in order to find the b
14=(-5/3)(9)+b
14=(-45/3)+b
14=(-15)+b
14+15=b
29=b
and so altogether our equation is y=(-5/3)x+29
Answer:
2 pieces.
Step-by-step explanation:
To identify how many pieces he can split with 8/10 of a candy bar, divide 8/10 by 1/3.
<u>Divide 8/10 by 1/3:</u>
<u>Find the Ricipricol, then flip the sign:</u>
<u>Multiply:</u>
<u />
2.4 represents how many pieces of chocolate he can make with 8/10 of a candy bar.
However, 2.4 pieces can't be made, therefore he can only make 2 <u>full</u> pieces.
Answer:I'd sayb
Step-by-step explanation:
Answer:
Step-by-step explanation:
x
2
+
x
−
6
=
(
x
+
3
)
(
x
−
2
)
x
2
−
3
x
−
4
=
(
x
−
4
)
(
x
+
1
)
Each of the linear factors occurs precisely once, so the sign of the given rational expression will change at each of the points where one of the linear factors is zero. That is at:
x
=
−
3
,
−
1
,
2
,
4
Note that when
x
is large, the
x
2
terms will dominate the values of the numerator and denominator, making both positive.
Hence the sign of the value of the rational expression in each of the intervals
(
−
∞
,
−
3
)
,
(
−
3
,
−
1
)
,
(
−
1
,
2
)
,
(
2
,
4
)
and
(
4
,
∞
)
follows the pattern
+
−
+
−
+
. Hence the intervals
(
−
3
,
−
1
)
and
(
2
,
4
)
are both part of the solution set.
When
x
=
−
1
or
x
=
4
, the denominator is zero so the rational expression is undefined. Since the numerator is non-zero at those values, the function will have vertical asymptotes at those points (and not satisfy the inequality).
When
x
=
−
3
or
x
=
2
, the numerator is zero and the denominator is non-zero. So the function will be zero and satisfy the inequality at those points.
Hence the solution is:
x
∈
[
−
3
,
−
1
)
∪
[
2
,
4
)
graph{(x^2+x-6)/(x^2-3x-4) [-10, 10, -5, 5]}
