Question 1 of 40

a population of 140000 grows 4% per year for 16 years. How much will the population be after 16 years?

Igoryamba

At the end of the Year 1 the population will be = 110,000 + 4% of 110,000 =P1At the end of the Year 2 the population will be=P1+ 4% of P1= 110,000 + 4% of 110,000 + 4% of (110,000 + 4% of 110,000) = 110,000 + 4% of (110,000+ 110,000 + 4% of 110,000) = 110,000 + 2*4% of 110,000 + (4%)2 of 110,000= P2At the end of the Year 3 the population will be= P2+ 4% of P2= 110,000 +2* 4% of 110,000 + (4%)2 of 110,000 + 4% of [ 110,000 +2* 4% of 110,000 + (4%)2 of 110,000] = 110,000 +2* 4% of 110,000 + (4%)2 of 110,000 + 4% of 110,000 + 2* (4%)2 of 110,000 + (4%)3 of 110,000 =110,000 +3* 4% of 110,000 +3* (4%)2 of 110,000 + (4%)3 of 110,000 =P3At the end of the Year 4 the population will be= P3+ 4% of P3=110,000 +3* 4% of 110,000 +3* (4%)2 of 110,000 + (4%)3 of 110,000 +4% of [110,000 +3* 4% of 110,000 +3* (4%)2 of 110,000 + (4%)3 of 110,000] =110,000 +4* 4% of 110,000 + 6*(4%)2 of 110,000+4* (4%)3 of 110,000+ (4%)4 of 110,000 Now if we substitute n for 110,000 and r for 4% yearly rate of increase, we can rewrite,Before Year 1, at Year 0, the population, P0= n = n(1+r)0At the end of the Year 1 the population , P1= n+rn= x(1+r)1At the end of the Year 2 the population , P2= n+2rn+r2n =n(1+2r+r2)=n(1+r)2At the end of the Year 3 the population , P3= n+3rn+2r2n+r3n=n(1+3r+3r2+r3)=x(1+r)3At the end of the Year 4 the population , P4= n+4rn+6r2n+4r3n+r4n=n(1+r)4.
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At the end of the Year n the population , Px=n+nrx+(x-1)r2n+(x-2)r3n+...........+(x-x+2)r(x-1)x+(x-x+1)rxn=n(1+r)x.....At the end of the Year 16 the population , P16= n+16rn+15r2n+14r3n+.............+3r14n+2r15n+r16n=n(1+r)16 Thus under given condition of rate of growth, the Population P(x) at xth year will be P(x)=n(1+r)x Therefore, a population of 110,000 growing at 4% per year, in 16 years will be= 110,000(1+4/100)16= 110,000(1.04)16=206027.93702999115428132473599427≈206028

I hope this is helpful. I found the solution on the internet. Hope you have a good day and bye.

3 0

3 years ago

Kyle needs to build a crate in the shape of a rectangular prism. The crate must have a volume of 160 cubic feet, and a height of

MAXImum [283]

Answer:

Step-by-step explanation:

Given :-

Volume = 160 cu. ft.

Height = 4 ft.

To Find :-

Base Area

Relation :-

Volume = Base Area x Height

Solving :-

Base Area = 160/4

= <u>40 sq. ft.</u>

3 0

2 years ago

For the following conditional, identify the converse and the truth value of the converse:

melamori03 [73]

The answer to the question is B

4 0

3 years ago

Read 2 more answers

Drag the tiles to the correct boxes to complete the pairs.Not all tiles will be used match the equations representing parabolas

IceJOKER [234]

Answer:

$y=-8.08$ -------> $y+8=3(x+2)^{2}$

$y=14.25$ -------> $y-14=-(x-3)^{2}$

$y=-7.625$ -----> $y+7.5=2(x+2.5)^{2}$

$y=17.25$ -------> $y-17=-(x-3)^{2}$

$y=-7.25$ -------> $y+7=(x-4)^{2}$

$y=6.25$ -------> $y-6=-(x-1)^{2}$

Step-by-step explanation:

we know that

The standard form of a vertical parabola is equal to

$(x-h)^{2}=4p(y- k)$

where

(h,k) is the vertex

the focus is (h, k + p)

and

the directrix is y = k - p

Part 1) we have

$y+8=3(x+2)^{2}$

Convert to standard form

$(x+2)^{2}=(1/3)(y+8)$

The vertex is the point $(-2,-8)$

$h=-2,k=-8$

$4p=1/3$

$p=1/12$

the directrix is equal to

$y = k-p$ -----> $y=-8-(1/12)=-8.08$

Part 2) we have

$y-14=-(x-3)^{2}$

Convert to standard form

$(x-3)^{2}=-(y-14)$

The vertex is the point $(3,14)$

$h=3,k=14$

$4p=-1$

$p=-1/4$

the directrix is equal to

$y = k-p$ -----> $y = 14-(-1/4)=14.25$

Part 3) we have

$y+7.5=2(x+2.5)^{2}$

Convert to standard form

$(x+2.5)^{2}=(1/2)(y+7.5)$

The vertex is the point $(-2.5,-7.5)$

$h=-2.5,k=-7.5$

$4p=1/2$

$p=1/8$

the directrix is equal to

$y = k-p$ -----> $y=-7.5-(1/8)=-7.625$

Part 4) we have

$y-17=-(x-3)^{2}$

Convert to standard form

$(x-3)^{2}=-(y-17)$

The vertex is the point $(3,17)$

$h=3,k=17$

$4p=-1$

$p=-1/4$

the directrix is equal to

$y = k-p$ -----> $y = 17-(-1/4)=17.25$

Part 5) we have

$y+7=(x-4)^{2}$

Convert to standard form

$(x-4)^{2}=(y+7)$

The vertex is the point $(4,-7)$

$h=4,k=-7$

$4p=1$

$p=1/4$

the directrix is equal to

$y = k-p$ -----> $y=-7-(1/4)=-7.25$

Part 6) we have

$y-6=-(x-1)^{2}$

Convert to standard form

$(x-1)^{2}=-(y-6)$

The vertex is the point $(1,6)$

$h=1,k=6$

$4p=-1$

$p=-1/4$

the directrix is equal to

$y = k-p$ -----> $y=6-(-1/4)=6.25$

4 0

3 years ago

If one acute angle of a right triangle measure 37 what's the measure of the other acute angle

Ghella [55]

53°

Step-by-step:

- All angles in a triangle add up to 180°.

- Since your triangle is a right angle triangle, one of the angles are 90°.

- You already know another one, 37°.

- All you have to do to find the last one is to subtract the two you already know from 180.

180 - (90+37)

= 180 - 127

= 53

The measure of the last angle is 53°.

5 0

3 years ago