IQR: Need help asap! 20 points! What is the interquartile range of the data set?
1 answer:
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<h2>Hello!</h2>
Since there is no additional information, we can assume that the given angles are respect to the horizontal axis (x), so
The answer is:
Magnitude: 95.14 lbs
Direction: 80° respect to the x-axis
<h2>Why?</h2>Since there is no additional information about the given angles, we can assume that both angles are respect to the horizontal axis (x), positive direction to x-axis positive directions (right) and above x-axis.
<h2>Calculations:</h2>100 pounds (lb) force, 50° angle:
50 pounds (lb) force, 160° angle:
So,
For x-axis forces we have:
64.28lbs (positive direction)
-46.98lbs (negative direction)
Then,
(positive direction)
Fox y-axis forces we have:
76.60lbs (positive direction)
17.10 lbs (positive direction)
Then,
(positive direction)
So, we have the two components values of the acting force:
17.3 lbs for the x-axis and 93.7 lbs for the y-axis.
Therefore,
We have to calculate the angle between both resultant force components:
Let's calll it α
So,
Hence, the angle between both resultant force components is 80 °, meaning that the resultant force direction is positive, above the x-axis.
Now we have to calculate the magnitude of the resultant force since the sum of both resultant force components is equal to the hypotenuse of the formed triangle, we have that:
So, we have that:
- Resultant force magnitude is equal to 95.14 lbs
- Direction is 80° respect to the x-axis.
Have a nice day!